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kipiarov [429]
3 years ago
11

The sound source of a ship's sonar system operates at a frequency of 18.0 kHzkHz . The speed of sound in water (assumed to be at

a uniform 20∘C)∘C) is 1482 m/sm/s. The ship is at rest in the water.
(a) What is the wavelength of the waves emitted by the source?
(b) What is the difference in frequency between the directly radiated waves and the waves reflected from a whale traveling directly toward the ship at 4.95 m/s? The ship is at rest in the water.
Physics
1 answer:
Flura [38]3 years ago
5 0

Answer:

Explanation:

a ) wave length of waves in water

= velocity / frequency

= 1482 / (18 x 1000)

= .0823 m

= 8.23 cm

b ) Applying Doppler's effect relation

frequency of reflected wave

= 18000 [ 1482 / (1482 - 4.95 ) ]

= 18000 x 1.003385

= 18061

Difference in frequency= 61 Hz

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snow_lady [41]

Answer:

<u><em>The truck was moving 16.5 m/s during the time it took to stop, which was 3 seconds. </em></u>

  • <u><em>Initial velocity = 33 m/s</em></u>
  • <u><em>Final velocity = 0 m/s</em></u>
  • <u><em>Average velocity = (33 + 0) / 2  m/s = 16.5 m/s</em></u>

Explanation:

  1. <u><em>First, how long does it take the truck to come to a complete stop?</em></u>
  1. <u><em>( 33 m/s ) / ( 11 m / s^2 ) = 3 seconds</em></u>
  1. <u><em>Then we can look at the average velocity between when the truck started decelerating and when it came to a complete stop. Because the deceleration is constant (always 11m/s^2) we can use this trick.</em></u>
4 0
3 years ago
What is an RC circuit? 
cupoosta [38]
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8 0
3 years ago
What factors determine the presence of electrical energy?
luda_lava [24]
One of them would be power source.
8 0
4 years ago
if 100 kilojoules of energy is used to heat 500 grams of water what is the temperature change of the water​
Serjik [45]

Answer:

47.8 °C

Explanation:

Use the heat equation:

q = mCΔT

where q is the heat absorbed/lost,

m is the mass of water,

C is the specific heat capacity,

and ΔT is the change in temperature.

Here, q = 100 kJ, m = 0.5 kg, and C = 4.184 kJ/kg/°C.

100 kJ = (0.5 kg) (4.184 kJ/kg/°C) ΔT

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6 0
3 years ago
A projectile is shot at an angle 45 degrees to the horizontalnear the surface of the earth but in the absence of air resistance.
juin [17]

Answer:

Explanation:

Given

For first case

launch angle \theta =45^{\circ}C

at highest point h=150 m/s

150=u\cos 45

u=\frac{150}{\cos 45}=212.132 m/s

For second case

\theta _2=37^{\circ}C

at highest Point velocity is u\cos \theta _2

=212.132\times \cos 37

=169.41 m/s

as there is no acceleration in x direction therefore horizontal velocity is same          

7 0
3 years ago
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