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stira [4]
3 years ago
11

They preserve many good__for us(from history of nepal)​

Physics
1 answer:
vampirchik [111]3 years ago
6 0

Answer:

They preserve many good_from historyof nepal_for us(from history of nepal)

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A transformer has two sets of coils, the primary with N1 = 160 turns and the secondary with N2 = 1400 turns. The input rms volta
vovikov84 [41]

To solve the problem it is necessary to apply the concepts related to the voltage in a coil, through the percentage relationship that exists between the voltage and the number of turns it has.

So things our data are given by

N_1 = 160

N_2 = 1400

\Delta V_{1rms} = 62V

PART A) Since it is a system in equilibrium the relationship between the two transformers would be given by

\frac{N_1}{N_2} = \frac{\Delta V_{1rms}}{\Delta V_{2rms}}

So the voltage for transformer 2 would be given by,

\Delta V_{2rms} = \frac{N_2}{N_1} \Delta V_{1rms}

PART B) To express the number value we proceed to replace with the previously given values, that is to say

\Delta V_{2rms} = \frac{N_1}{N_2} \Delta V_{1rms}

\Delta V_{2rms} = \frac{1400}{160} 62V

\Delta V_{2rms} = 1446.66V

7 0
3 years ago
A bullet was fired from a gun. The bullet had a mass of 50g and the kinetic energy of the bullet was 25 kJ. How fast did it go?
Elenna [48]

Answer:

given \:  \\ mass \: (m) = 50g \\ kinetic \: enegy \: (k.e) = 25kj \\ velocity(v) = x \\ form \\ k.e =  \frac{1}{2}  \times MV ^{2}  \\ 25 =  \frac{1}{2}  \times 50 \times v {}^{2}  \\ 25 = 25 \times v {}^{2} \\ v {}^{2}  =  \frac{25}{25}  \\ v {}^{2}  = 1 \\ v =  \sqrt{1}  \\ v = 1ms {}^{ - }

the car it go fast with velocity 1m/s

5 0
3 years ago
I'd: 9872093250, password: qqqqq ,join the meeting​
kirill115 [55]
Sheeeeeeeeeeeeeeeeeeeeeesh
4 0
3 years ago
An arrow is launched upward with an initial speed of 100 meters per second (m/s). The equations above describe the constant-acce
BigorU [14]

Answer:

510 m

Explanation:

The arrow is fired upward, so the motion of the arrow is a free fall motion, therefore we can find the maximum height by using the suvat equation

v^2-u^2=2as

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement

Here we have:

v = 0 (at the point of maximum height, the velocity of the arrow is zero)

u = 100 m/s (initial velocity)

a=g=-9.8 m/s^2  (acceleration of gravity, downward)

s = ? is the maximum height

Solving for s,  we find the maximum height of the arrow:

s=\frac{v^2-u^2}{2a}=\frac{0-100^2}{2(9.8)}=510 m

5 0
4 years ago
What is the tiny particle that is the fundamental building block of a substance
Ksju [112]
The basic building block of matter are Atoms. Atoms are also made up of Electrons, Protons, and Neutrons.

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3 years ago
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