<h2>Given↷</h2>
<h2>To find↷</h2>
<h2>Answer↷</h2>
<h2>Solution↷</h2>
We know that,
two angles which are formed by the intersection of two lines ,are <u>equal</u> and are called <u>vertically</u><u> </u><u>opposite</u><u> </u><u>angles.</u>
<u>ATQ,</u>
angle x lies on a line same as the other given angle which is intersected by an another line ,
hence,
The correct answers are :
y=-1/2x+5 is parallel.
-2x+y=-4 is perpendicular.
-x+2y=2 is neither.
x+2y=2 is parallel.
<h3>What are parallel lines and perpendicular lines ?</h3>
It is argued that two non-vertical lines in the same plane that have the same slope are parallel.
In terms of geometry, parallel lines are two separate lines that never cross each other and are located in the same plane. They may be vertical or horizontal. Examples of parallel lines can be found all around us on railroad tracks, in lines of notebooks, and at zebra crossings in daily life. It is impossible for two parallel lines to cross. Perpendicular lines are those that cross at a right angle when two non-vertical lines in the same plane.
Perpendicular lines are two different lines that cross at a right angle of 90 degrees.
To know more about lines and angles you may visit:
brainly.com/question/6636431
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Answer:
13- A 14-B
Step-by-step explanation:
You take the formula (x1+x2/2, y1+y2/2) and plug in accordingly. For instance, when you plug the values in for 13, you would get:
x1+-9/2, y1+7/2= -8,2
All you have to do from there is a simple guess and check or plug in each number from the multiple answer choices you have. You should then get A (-7,-3) Do the same with 14, in which you should get B (11,-20)
Sorry for taking so long to answer but hope this kind of helps.
Answer:
5 is the median
Step-by-step explanation:
The "median" is the "middle" of the set of numbers. Considering there are 13 total numbers, making it un-even, there can be an equal amount of numbers taken off of each side with a middle number remaining. That middle number will be your median..
Answer:
x = 0
Step-by-step explanation:
