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USPshnik [31]
3 years ago
8

A rancher has a roll of fencing to enclose a rectangular area. The table shows how the area that the rancher can enclose with th

e fencing depends on the width of the rectangle.
Width (w)ft Area (A) ft2
10 900
20 1,600
30 2,100

Which quadratic equation gives the area A of the rectangle in square feet given its width in w feet?

A. A(w)= -w to the power of 2+200w
B. A(w)= -w to the power of 2+100w
C. A(w)= w to the power of 2+40w
D. A(w)= w to the power of 2+90w
Mathematics
2 answers:
Free_Kalibri [48]3 years ago
8 0
Checking for each option

Option A: A(w) = -w^2+200w

Substitute w = 10 and check if we'd get 900 as the answer
A(10) = -(10)^2+200(10) = -100+2000 = 1900

Option B: A(w) = -w^2+100w
Substitute w = 10 and check if we'd get 900 as the answer
A(10)=-(10)^2+100(10)=-100+1000=900

Option C: A(w)=w^2+40w
Substitute  w = 10 and check if we'd get 900 as the answer
A(10) = 10^2+40(10)=100+400=500

Option D: A(w) = w^2+90w
Substitue w = 10 and check if we'd get 900 as the answer
A(10)=10^2+90(10) = 100+900=1000

Answer: Option B



Setler [38]3 years ago
7 0
10, 900
and then the second one
B
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y= 20x

Step-by-step explanation:

40/2=100/5=200/10=20  linear function.

I hope this help you

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a. Find symmetric equations for the line that passes through the point (4, −4, 8) and is parallel to the vector −1, 4, −3b. Find
daser333 [38]

The line has equation

\vec r(t)=(4,-4,8)+(-1,4,-3)t

where t is any real number. (-1,4,-3)t is the line containing all scalar multiples of the vector (-1, 4, -3); we add (4, -4, 8) to shift the line so that it passes through this point while remaining parallel to the the line.

To get the symmetric form, we have

\begin{cases}x(t)=4-t\\y(t)=-4+4t\\z(t)=8-3t\end{cases}

Solving for t in each equation gives the symmetric form,

t=\boxed{4-x=\dfrac{y+4}4=\dfrac{8-z}3}

The line has intercepts in the coordinate planes wherever either the x, y, or z coordinate is 0.

xy-plane:

z=0\implies\begin{cases}4-x=\frac83\\\frac{y+4}4=\frac83\end{cases}\implies\left(\dfrac43,\dfrac{20}3,0\right)

yz-plane:

x=0\implies\begin{cases}\frac{y+4}4=4\\\frac{8-z}3=4\end{cases}\implies\left(0,12,-4\right)

xz-plane:

y=0\implies\begin{cases}4-x=1\\\frac{8-z}3=1\end{cases}\implies\left(3,0,5\right)

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Triangle ABC is dilated to produce triangle A'B'C' with scale factor 3/4. which describes the relationship between the two trian
Nadya [2.5K]

Answer:

ΔA'B'C' is a reduction of ΔABC and ΔA'B'C' is similar to ΔABC.

Step-by-step explanation:

It is given that the triangle ABC is dilated to produce triangle A'B'C' with scale factor 3/4.

If a figure is dilated then preimage and image are similar.

If scale factor is between 0 to 1, then preimage is reduction of image.

If scale factor is more that 1, then preimage is enlargement of image.

If scale factor is 1, then preimage is congruent to the image.

We know that

\frac{3}{4}=0.75

So,

0

Therefore, the ΔA'B'C' is a reduction of ΔABC and ΔA'B'C' is similar to ΔABC.

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