Total squares= 12
1x + 2x = 12
3x = 12
3x/3 = 12/3
x = 4
1x4 = 4
2x4 = 8
So. C is the answer
<h2>169</h2>
In this problem, we need to use squaring method.
5² means 5 × 5
5² = 25
12² means 12 × 12
12² = 144
So, simplify these statements:
5² × 12²
25 + 12² (Simplify 5², which means 5 × 5)
25 + 144 (Simplify 12², which means 12 × 12)
We get the answer:
25 + 144 =
<h3>169</h3>
<em>Hope this helps :)</em>
now, we're making the assumption that the front and back of the tent are trapezoidal, Check the picture below.
![\textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h=height\\ a,b=\stackrel{parallel~sides}{bases}\\[-0.5em] \hrulefill\\ h=32\\ a=23\\ b=36.5 \end{cases}\implies \begin{array}{llll} A=\cfrac{32(23+36.5)}{2}\implies A=952 \\\\\\ \stackrel{\textit{twice that much}}{2A=1904} \end{array}](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20trapezoid%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7Bh%28a%2Bb%29%7D%7B2%7D~~%20%5Cbegin%7Bcases%7D%20h%3Dheight%5C%5C%20a%2Cb%3D%5Cstackrel%7Bparallel~sides%7D%7Bbases%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20h%3D32%5C%5C%20a%3D23%5C%5C%20b%3D36.5%20%5Cend%7Bcases%7D%5Cimplies%20%5Cbegin%7Barray%7D%7Bllll%7D%20A%3D%5Ccfrac%7B32%2823%2B36.5%29%7D%7B2%7D%5Cimplies%20A%3D952%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Btwice%20that%20much%7D%7D%7B2A%3D1904%7D%20%5Cend%7Barray%7D)
Answer:
27
Step-by-step explanation:
(5+√2)²
you distribute the ² in the ()
so 5²+√2²
5²=25
√2²=2 because the √ and ² cancel each other out and you get 2
so now you have
25+2
which equals
27
Y= 26 & x=35 hope I did it on time!
