Could you add a image or message me the image, after you do that you can comment on this and I’ll come back to it.
For this case we have that by definition, the equation of the line of the slope-intersection form is given by:
Where:
m: It's the slope
b: It is the cut-off point with the y axis
We have two points through which the line passes:
We found the slope:
Substituting we have:
Thus, the equation is of the form:
We substitute one of the points and find the cut-off point:
Finally, the equation is:
ANswer:
The first one -8-13-18
calculate it
2. (-1,4) because it’s the only point in the intersection of both intersections. All the other points only fall into the solution of one inequality or in the case of 4 none
Given 10 independent part,
No mean shift
This implies that,
The mean is 10
It also means that the variance is 0
And also the standard deviation is 0.
Then, the sigma deviation is
3×0+10=10.
Since none of the data is at such a high point, the manufacturing testing process has not yet reached three-sigma quality levels.
Since we have this let use the special consideration
Three-sigma limits set a range for the process parameter at 0.27% control limits. Three-sigma control limits are used to check data from a process and if it is within statistical control
Therefore,
The 0.27% will give the defective
2.7/100×10=0.027
Then, the none defective is
1-0.027=0.973
Which is 97.3%
