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solniwko [45]
3 years ago
9

Write the linear equation in slope intercept form 1,3 and -3,-5

Mathematics
1 answer:
oksian1 [2.3K]3 years ago
3 0

For this case we have that by definition, the equation of the line of the slope-intersection form is given by:

y = mx + b

Where:

m: It's the slope

b: It is the cut-off point with the y axis

We have two points through which the line passes:

(x_ {1}, y_ {1}) :( 1,3)\\(x_ {2}, y_ {2}): (- 3, -5)

We found the slope:

m = \frac{y_ {2} -y_ {1}} {x_ {2} -x_ {1}}

Substituting we have:

m = \frac {-5-3} {- 3-1} = \frac {-8} {- 4} = 2

Thus, the equation is of the form:

y = 2x + b

We substitute one of the points and find the cut-off point:

3 = 2 (1) + b\\3 = 2 + b\\3-2 = b\\b = 1

Finally, the equation is:

y = 2x + 1

ANswer:

y = 2x + 1

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eimsori [14]
B.) Hibiscus Street 

The key thing to remember is the slope of the lines. The equation for a line in slope intercept form is
y = ax + b
where
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So the equation for Oak Street is y = 2/3x - 7. So it's slope is 2/3. And any street that has the same slope will be given a tree name. And any street that's perpendicular will be given a flower name. You can determine is a line is perpendicular if it has a slope that's the negative reciprocal. So a street that's perpendicular to Oak street will have a slope of -3/2.

Now you've just been given the equation to a new street that's y = -3/2x - 2. Since the slope is -3/2 and Oak street has a slope of 2/3, the new street is perpendicular to Oak street. And given the naming scheme, that means that the new street will have the name of a flower. So let's look at the available street names and pick a flower.
<span>
A.) Weeping Willow Street
* Nope a Weeping Willow is a tree. So this name won't work.
 
B.) Hibiscus Street 
* Yes. A Hibiscus is a flower, so this name is suitable.

C.) Oak Street 
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D.) Panther Street
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</span>
6 0
3 years ago
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