Question

Write the linear equation in slope intercept form 1,3 and -3,-5

Answer 1

For this case we have that by definition, the equation of the line of the slope-intersection form is given by:

$y = mx + b$

Where:

m: It's the slope

b: It is the cut-off point with the y axis

We have two points through which the line passes:

$(x_ {1}, y_ {1}) :( 1,3)\\(x_ {2}, y_ {2}): (- 3, -5)$

We found the slope:

$m = \frac{y_ {2} -y_ {1}} {x_ {2} -x_ {1}}$

Substituting we have:

$m = \frac {-5-3} {- 3-1} = \frac {-8} {- 4} = 2$

Thus, the equation is of the form:

$y = 2x + b$

We substitute one of the points and find the cut-off point:

$3 = 2 (1) + b\\3 = 2 + b\\3-2 = b\\b = 1$

Finally, the equation is:

$y = 2x + 1$

ANswer:

$y = 2x + 1$