X + k y = 1
k x + y = 1 / * ( - k )
----------------
x + k y = 1
- k² x - k y = - k
--------------------
x - k² x = 1 - k
x ( 1 - k² ) = 1 - k
x = ( 1 - k ) / ( 1 - k² ) = ( 1 - k ) / ( 1 - k ) ( 1 + k )
y = 1 - k( 1 - k )/( 1 - k² )
y = ( 1 - k ) / ( 1 - k² ) = ( 1 - k ) / ( 1 - k ) ( 1 + k )
a ) For k = - 1 this system has no solution.
b ) For k ≠ - 1 and k ≠ 1, the system has unique solution:
( x , y ) = ( 1/ (1 + k) , 1/( 1 + k ) ).
c ) For k = 1, there are infinitely many solutions.
I is C because you use the pythag theorem
Answer:
D part
Step-by-step explanation:
3x + 80⁰ + 2x = 180⁰ (By Linear Pair)
5x + 80⁰ = 180⁰
5x = 100⁰
x = 20⁰
Hope it helps :)
Answer:
c = 2
Step-by-step explanation:
Since 16 is over the variable c, first multiply both sides by c so the variable is not in the denominator of the fraction.
16/c(c) = 8(c)
16 = 8c Next, divide both sides by 8 to solve for c.
c = 2
Answer:
-2
Step-by-step explanation:
I took the test :)