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vladimir1956 [14]
4 years ago
12

find three consecutive even integers such that the sum of the smallest integer and twice the median integer is 20more than the l

argest integer.
Mathematics
1 answer:
3241004551 [841]4 years ago
3 0
X = smallest; x + 2 = middle, and x + 4 = largest
x + 2(x+2) = 20 + x + 4
x + 2x + 4=24 +x
3x + 4 = 24 + x
2x = 20
x = 10
so the three integers are 10, 12, and 14
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Step-by-step explanation:

<em>Why numbers greater than 23 can be made</em>

From any number that Larry can make that includes an appropriate number of stamps, Larry can ...

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Clearly, for Larry to be able to continue adding any number, he must start with a number that contains at least 6×4 cents = 24 cents.

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<em>Why 23 cannot be made</em>

For 23 cents, the number of stamps must include 0, 1, or 2 9-cent stamps, so there are 3 cases to try for making 23:

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