Question

ASAP PLEASE ANSWER quadrilateral ABCD is dilated at center (0,0) with scale factor 1/2 to form quadrilateral A'B'C'D'. wha is the length of A'B'?
a. sqrt5

b.2

c.10

d.2sqrt5

Answer 1

Answer:

$|A'B'|=\sqrt{5}$

Step-by-step explanation:

The points A and B have coordinates at (0,4) and (4,2) respectively.

The distance formula can be used to find the length of AB.

$|AB|=\sqrt{(4-0)^2+(2-4)^2}$

$|AB|=\sqrt{(4)^2+(-2)^2}$

$|AB|=\sqrt{16+4}$

$|AB|=\sqrt{20}$

$|AB|=2\sqrt{5}$

Since quadrilateral ABCD was enlarged with  a scale factor of $\frac{1}{2}$.

The length of A'B' is

$\frac{1}{2}|AB|$

$=\frac{1}{2}\times2\sqrt{5}$

$\therefore |A'B'|=\sqrt{5}$

Answer 2

Answer:

the answer is a

Step-by-step explanation: