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Sholpan [36]
3 years ago
5

Bailey is paid a royalty of 11.3% on the net sales of his book. The net sales of his book in the

Mathematics
1 answer:
ratelena [41]3 years ago
4 0

Answer:

B

Step-by-step explanation:

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15/3 = 5
There are 5 doughnuts left.
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What is the measure of the missing angle?​
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115

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Mike is making macaroni salad. For each bowl of macaroni salad, he needs 1/3 cup of macaroni. How many cups of macaroni will he
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Question 1 help!? Asap
Paha777 [63]

Hi!

If the perimeter of the triangle is 41, then x is:

5x + 2 + 6x - 3 + 3x = 41

5x + 6x + 3x = 41 + 3 - 2

14x = 42

x = 42/14

x = 3

The x is 3.

7 0
3 years ago
Is the sum of the areas of two smaller squares equal to the area of a large square if the side lengths of the squares are 8 feet
Ivanshal [37]

No, the sum of the areas of two smaller squares is not equal to the

area of a large square

Step-by-step explanation:

To solve this problem let us do these steps

1. Find the area of the larger square

2. Find the area of the two smaller squares

3. Add the areas of the two smaller squares

4. Compare between the sum of the areas of the 2 smaller squares

   and the area of the larger square

The area of a square is s²

The length of the side of the larger square is 8 feet

∵ s = 8 feet

∴ Area of the larger square = (8)² = 64 feet²

The lengths of the sides of the smaller squares are 5 feet and 3 feet

∵ s = 5 feet

∴ The area of one of the smaller square = (5)² = 25 feet²

∵ s = 3 feet

∴ The area of the other smaller square = (3)² = 9 feet²

The sum of the areas of the two smaller squares = 25 + 9 = 34 feet²

∵ The area of the larger square is 64 feet²

∵ The sum of the areas of the two smaller squares is 34 feet²

∵ 64 ≠ 34

∴ The sum of the areas of two smaller squares is not equal to the

   area of a large square

<em>No, the sum of the areas of two smaller squares is not equal to the</em>

<em>area of a large square</em>

Learn more:

You can learn more about the areas of figures in brainly.com/question/3306327

#LearnwithBrainly

4 0
4 years ago
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