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3 years ago

12

Which of the following equations is equal to 3x^2+27?

1 answer:

Natalka [10]3 years ago

8 0

Answer:

What are the possible answers?

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What is the relationship between the lines determined by the following two equations?

oksano4ka [1.4K]

Answer:

C. They are the same line.

Step-by-step explanation:

In order to compare the linear equations given, they need to be in the same form. The best form in order to evaluate slope and y-intercept is slope-intercept form, y = mx + b. Since the second equation is already in slope-intercept form, we need to use inverse operations to convert the first equation:

6x - 2y = 16 ---- 6x - 2y - 6x = 16 - 6x ---- -2y = -6x + 16

-2y/-2 = -6x/-2 + 16/-2

y = 3x - 8

Since both equations are in the form y = 3x - 8, then they are both the same line.

4 0

3 years ago

ezekiel has $250 in his bank account he deposts $35 from his birthday and then buys clothes for school for $75

Semmy [17]

Answer:

$140

Step-by-step explanation:

i assume ur asking for how much is left over

250-35= 215

215-75= 140

$140 left

6 0

3 years ago

Three cans of tuna costs $1.50. What is the cost of one can of tuna

lord [1]

The cost of one can of tuna is $1.50/3, or $0.50 per can.

6 0

3 years ago

Read 2 more answers

What is the y-coordinate of the point that divides the directed

e-lub [12.9K]

Answer:

(D)5

Step-by-step explanation:

Given the point J(-3,1) and K(8,11).

The line segment that divides the segment from J to K in any given ratio can be determined using the formula.

$P(x,y)=\left(\dfrac{mx_2+nx_1}{m+n} ,\dfrac{my_2+ny_1}{m+n}\right)$

In the given case:

$(x_1,y_1)=(-3,1), (x_2,y_2)=(8,11)$ , m:n=2:3

Since we are to determine the y-coordinate of the point that divides JK into a ratio of 2:3, we have:

$\dfrac{my_2+ny_1}{m+n}=\dfrac{2*11+3*1}{3+2}\\\\=\dfrac{22+3}{5}\\\\=\dfrac{25}{5}\\\\=5$

The y-coordinate of the point that divides the directed line segment from J to K into a ratio of 2:3 is 5.

The correct option is D.

3 0

3 years ago

Please answer the question!

Airida [17]

ANSWER

$Area = 2\sqrt{3} \: {cm}^{2}$

EXPLANATION

We need to use the Pythagoras Theorem to find the height of the triangle.

${a}^{2} + {b}^{2} = {c}^{2}$

$({2 \sqrt{3}) }^{2} + {b}^{2} = {4}^{2}$

$12 + {b}^{2} = 16$

${b}^{2} = 16 - 12$

${b}^{2} = 4$

Take positive square root to get;

$b = \sqrt{4} = 2$

Area =½bh

$Area = \frac{1}{2} \times 2\sqrt{3} \times 2$

$Area = 2\sqrt{3} \: {cm}^{2}$

7 0

3 years ago