Answer:
-1+5z, -25+20y, 4d+14, 2n-2, 40k+8, 8b+5, -9+22p
Step-by-step explanation:
1) -4+7z+3-2z
-1+5z
2) 15+4(5y-10)
15+20y-40
-25+20y
3) 2d+17-3-2d+4d
4d+14
4) 12n-8-2n+10-4
2n-2
5) 8(2k+1+3k)
16k+8+24k
40k+8
5) 4(2b+2)-3
8b+8-3
8b+5
6) -4+8p-6p-5+20p
-9+22p
Answer:
9 servings
There should be an answer to that. Answer: There are 9 servings. step- by- step Explanation: We would first divide 22.5/2.5. This will give us the amount of time 2.5 will go into 22.5, providing us with the amount of servings
Step-by-step explanation:
Answer:
7,700
Step-by-step explanation:
5 or more, raise the score
4 or less, let it rest
We're looking for
such that
, which requires



Integrating both sides of the first PDE wrt
gives

Differenting this wrt
gives


but we're assuming
is a function that doesn't depend on
, which is contradicted by this result, and so there is no such
and
is not conservative.
From the given the function, <span>y(t)=−t²+14t−40; the graph will be as shown below:
From the graph, it is evident that between the intervals 6</span>≤t≤8<span>:
The value of our function decreases over the given interval. Hence the answer is:
</span><span>a. The value of y(t) increases over the interval 6≤t≤7
</span>