If mountain mack splits his week evenly between carving fishing lures and duck decoys, what is the maximum number of fishing lur
1 answer:
Given the question:
Mountain Mark and Big Lake Bob spend their time carving fishing lures and duck decoys. The table below shows their production possibility schedule, which describes various combinations of fishing lures and duck decoys they each can carve efficiently in a week.
![\begin{center} \begin{tabular} {|c {2.3cm}|c {2.3cm}|c {2.3cm}|c {2.3cm}|} \multicolumn {4} {|c|} {Production Possibility Schedules}\\[1ex] \multicolumn {2} {|c|} {Mountain Mark}&\multicolumn {2} {|c|} {Big Lake Bob}\\[1ex] Fishing Lures&Duck Decoys&Fishing Lures&Duck Decoys\\[1ex] 40&0&100&0\\ 32&10&80&6\\ 24&20&60&12\\ 16&30&40&18\\ 8&40&20&24\\ 0&50&0&30 \end{tabular} \end{center}](https://tex.z-dn.net/?f=%5Cbegin%7Bcenter%7D%0A%5Cbegin%7Btabular%7D%0A%7B%7Cc%20%7B2.3cm%7D%7Cc%20%7B2.3cm%7D%7Cc%20%7B2.3cm%7D%7Cc%20%7B2.3cm%7D%7C%7D%0A%5Cmulticolumn%20%7B4%7D%20%7B%7Cc%7C%7D%20%7BProduction%20Possibility%20Schedules%7D%5C%5C%5B1ex%5D%0A%5Cmulticolumn%20%7B2%7D%20%7B%7Cc%7C%7D%20%7BMountain%20Mark%7D%26%5Cmulticolumn%20%7B2%7D%20%7B%7Cc%7C%7D%20%7BBig%20Lake%20Bob%7D%5C%5C%5B1ex%5D%0AFishing%20Lures%26Duck%20Decoys%26Fishing%20Lures%26Duck%20Decoys%5C%5C%5B1ex%5D%0A40%260%26100%260%5C%5C%0A32%2610%2680%266%5C%5C%0A24%2620%2660%2612%5C%5C%0A16%2630%2640%2618%5C%5C%0A8%2640%2620%2624%5C%5C%0A0%2650%260%2630%0A%5Cend%7Btabular%7D%0A%5Cend%7Bcenter%7D)
<span>If mountain mack splits his week evenly between carving fishing lures and duck decoys, what is the maximum number of fishing lures and duck decoys he could carve?
From the table it can be seen that in a full week, if mountain mack is carving fishing lures only, he can carve 40 fishing lures. This means that in half of a week, he can carve 20 fishing lures.
Similarly, f</span><span>rom the table it can be seen that in a full week, if mountain mack is carving duck decoys only, he can carve 50 duck decoys. This means that in half of a week, he can carve 25 duck decoys.
</span>
Therefore, i<span>f mountain mack splits his week evenly between carving fishing lures and duck decoys, the maximum number of fishing lures and duck decoys he could carve are 20 fishing lures and 25 duck decoys.</span>
Mountain Mark and Big Lake Bob spend their time carving fishing lures and duck decoys. The table below shows their production possibility schedule, which describes various combinations of fishing lures and duck decoys they each can carve efficiently in a week.
<span>If mountain mack splits his week evenly between carving fishing lures and duck decoys, what is the maximum number of fishing lures and duck decoys he could carve?
From the table it can be seen that in a full week, if mountain mack is carving fishing lures only, he can carve 40 fishing lures. This means that in half of a week, he can carve 20 fishing lures.
Similarly, f</span><span>rom the table it can be seen that in a full week, if mountain mack is carving duck decoys only, he can carve 50 duck decoys. This means that in half of a week, he can carve 25 duck decoys.
</span>
Therefore, i<span>f mountain mack splits his week evenly between carving fishing lures and duck decoys, the maximum number of fishing lures and duck decoys he could carve are 20 fishing lures and 25 duck decoys.</span>
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Answer:
The 90% confidence interval of the population proportion is (0.43, 0.56).
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for population proportion <em>p</em> is:
The information provided is:
<em>X</em> = 74
<em>n</em> = 150
Confidence level = 90%
Compute the value of sample proportion as follows:
Compute the critical value of <em>z</em> for 90% confidence level as follows:
*Use a <em>z</em>-table.
Compute the 90% confidence interval of the population proportion as follows:
Thus, the 90% confidence interval of the population proportion is (0.43, 0.56).