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Blababa [14]
3 years ago
5

Each cube in this figure measures 1 centimeter on each side.

Mathematics
2 answers:
Zanzabum3 years ago
5 0

Answer:

84 cm cubed

Step-by-step explanation:

length is 4 and width is 7 and the height is 3 so it is 4*3*7 which is equal to 84

Naddik [55]3 years ago
5 0
Answer is 84 first do the bottom 4 x 7 x 3 which is 84
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-3p-(-8+4p) combining like terms & distributive property
Nutka1998 [239]
Work: -3p-(-8+4p)
Distribute
-3p+8-4p
Combine
-7p+8
Answer: -7p+8

Hope that helps
8 0
3 years ago
Read 2 more answers
Which is greater 15/27 or 16/24
Artemon [7]

Answer:

16/24

Step-by-step explanation:

let’s use the GCF of both which is 3 for 15/27

15/27 divided by 3 is 5/9

for 16/24 the gcf is 8

16/24 / 8 is 2/3

now we have to multiply 2/3 times 3

2/3 times 3 6/3 which is 2

so 16/24 is greater.

3 0
3 years ago
Martha is carrying her biology, science, and math textbooks. Her books weigh a total of 9 pounds. Her biology textbook weighs 3
Nata [24]
1 pound = 16 oz
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science textbook = 56oz

5 0
3 years ago
Solve for the variable b. 5a(b - c ) = d
Liula [17]
5a(b-c)=d. Here, we are trying to isolate the variable b.
Divide both sides by 5a: b-c=d/(5a)
Add c to both sides: b= \frac{d}{5a} +c
3 0
3 years ago
Read 2 more answers
The amount A of the radioactive element radium in a sample decays at a rate proportional to the amount of radium present. Given
slavikrds [6]

Answer:

a) \frac{dm}{dt} = -k\cdot m, b) m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }, c) m(t) = 10\cdot e^{-\frac{t}{2438.155} }, d) m(300) \approx 8.842\,g

Step-by-step explanation:

a) Let assume an initial mass m decaying at a constant rate k throughout time, the differential equation is:

\frac{dm}{dt} = -k\cdot m

b) The general solution is found after separating variables and integrating each sides:

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }

Where \tau is the time constant and k = \frac{1}{\tau}

c) The time constant is:

\tau = \frac{1690\,yr}{\ln 2}

\tau = 2438.155\,yr

The particular solution of the differential equation is:

m(t) = 10\cdot e^{-\frac{t}{2438.155} }

d) The amount of radium after 300 years is:

m(300) \approx 8.842\,g

4 0
3 years ago
Read 2 more answers
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