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belka [17]
3 years ago
13

Please help asap 30 pts

Mathematics
2 answers:
Soloha48 [4]3 years ago
7 0

the answer is c or 3

X=5/3,-1

scoundrel [369]3 years ago
4 0
The answer will be C because if you simply it it will be 6x-2+2=10

Eliminate the opposite which is -2 and 2

Then you are left with 6x=10

Divide both sides by 6 and you will get 5/3
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Select all the roots of the following equation.
strojnjashka [21]

Answer:

5, -9

Step-by-step explanation:

(x - 5)(x + 9) = 0    These are factors, to get the roots, just set each one equal to zero

x - 5 = 0

x = 5

x + 9 = 0

x = -9

6 0
3 years ago
Read 2 more answers
A true/false test has 40 questions. Suppose a passing grade is 30 or more correct answers. Test the claim that a student knows m
Angelina_Jolie [31]

Answer:

z≈3.16

p≈0.001

we reject the null hypothesis and conclude that the student knows more than half of the answers and is not just guessing in 0.05 significance level.

Step-by-step explanation:

As a result of step 2, we can assume normal distribution for the null hypothesis

<em>step 3:</em>

z statistic is computed as follows:

z=\frac{X-M}{\frac{\sqrt{p*(1-p)} }{\sqrt{N} } } where

  • X is the proportion of correct answers in the test (\frac{30}{40})
  • M is the expected proportion of correct answers according to the null hypothesis (0.5)
  • p is the probability of correct answer (0.5)
  • N is the total number of questions in the test (40)

z=\frac{0.75-0.50}{\frac{\sqrt{0.5*(0.5)} }{\sqrt{40} } } ≈ 3.16

And corresponding p value for the z-statistic is p≈0.001.

Since p<0.05, we reject the null hypothesis and conclude that the student knows more than half of the answers and is not just guessing in 0.05 significance level.

7 0
4 years ago
How do you calculate this?
Dmitry_Shevchenko [17]

d = 5.6t {}^{2}  \\ 1814.4 = 5.6 \times t {}^{2}  \\ t {}^{2}  = 1814.4 \div 5.6 \\ t {}^{2}  = 324 \\ t =  \sqrt{324}  \\ t = 18
7 0
3 years ago
Read 2 more answers
If (x, y) = (3, 4) is a solution of the simultaneous equations.
Vinvika [58]
The first thing you want to do is plug in x and y into both equations:

a(3) + b(4) = 4

b(3) + a(4) = 8

rearrange to line up a’s and b’s

3a + 4b = 4

4a + 3b = 8

now you want to choose a or b and multiply each equation by a number to make them have the same amount of a’s or b’s.

4(3a + 4b = 4) = 12a + 16b = 16

3(4a + 3b = 8) = 12a + 9b = 24


Now we subtract the bottom equation from the top and solve for b:

12a + 16b - (12a + 9b) = 16 - 24

7b = -8

b = -8/7


Now we plug back in for b to one of the original equations:

3a + 4(-8/7) = 4

3a + (-32/7) = 4

3a - (32/7) = 4

3a = 4 + (32/7)

3a = (28/7) + (32/7)

3a = 60/7

a = (60/7)/3 = 20/7.


Finally, plug a and b in together to double check using the second equation.

4a + 3b = 8

4(20/7) + 3(-8/7) = ?

(80/7) - (24/7) = ?

56/7 = 8.
4 0
3 years ago
Solve -6 (4-x) &lt;-4 (x + 1).<br> O A. x ≤2<br> B. x &gt; 3<br> OC. x &lt;3<br> OD. 2
emmainna [20.7K]

Answer:

A

Step-by-step explanation:

-6(4 - x) <= -4(x + 1)

-24 + 6x <= -4x - 4

-24 + 10x <= -4

10x <= 20

x <= 2

5 0
2 years ago
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