Question

Is x-2 a factor of 4x^5 +5x^4 +1?

Answer 1

Answer:

No

Step-by-step explanation:

By the Factor theorem

If (x - h) is a factor of f(x) then f(h) = 0

Here (x - 2) with h = 2 and f(x) = 4$x^{5}$ + 5$x^{4}$ + 1 , then

f(2) = 4$(2)^{5}$ + 5$(2)^{4}$ + 1

     = 4(32) + 5(16) + 1

     = 128 + 80 + 1

     = 209

Since f(2) ≠ 0 then ( x - 2) is not a factor