Answer:
m ∠JPN = 131°
Step-by-step explanation:
m ∠JPL = m ∠MPK Vertical angles are =
7x + 19 = 11x -17 Substitution
- 4x = -36 Algebra: Solving for x
x = 9 Algebra: Solving for x
m ∠JPL = 82° Substitution x = 9 into m ∠JPL = 7x +19
m ∠JPL + m ∠LPK = 180° Definition of linear pair/supplement
angles = 180°
82° + m ∠LPK = 180° Substitution
m ∠LPK = 98° Algebra
m ∠LPK = m ∠LPN + m ∠NPK Angle addition Theorem
PN bisects ∠LPK Given
m ∠LPN = m ∠NPK Definition of angle bisector
98 ° = 2 ( m ∠LPN) Substitution
m ∠LPN = 49° Algebra
m ∠JPN = m ∠JPL + m ∠LPN Angle Addition
m ∠JPN = 82° + 49° Substitution
m ∠JPN = 131° Addition
The initial dimenssions of the park lot are:
length: 140 ft
width: 90 ft
initial area: 140 * 90 = 12,600 ft^2
Area increased 29% = 12,600 * 1.29 = 16,254 ft^2
width of the strips: x
New length: 140 + x
New width: 90 + x
New area: (140+x)(90+x) = 16,254
Solution of the equation:
12600 + 230x + x^2 = 16254
=> x^2 + 230x - 3654 = 0
Use the quadratic formula.
x = {-230 +/- √[ 230^2 - 4*1*(-3654) ]} / 2 =
x = 14.92
The other solution is negative so it is discarded.
Answer: 15 ft
Powers of ten! is the answer
Answer: 30.048
Try a calculator, it can help a lot!
Answer:
yes you just have to solve for both x and y in the top system and then solve the other systems to find out which one has the same solutions
Step-by-step explanation:
hope this helps!
