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Snowcat [4.5K]
3 years ago
8

It took Mary 40 minutes to run 8 laps around the playground, if she spent the same time running each lap, how long would it take

to run 9 laps?
Mathematics
2 answers:
Sergeeva-Olga [200]3 years ago
8 0

Answer:

it should take her 45 minutes to run 9 laps

Step-by-step explanation:

40/8 = 5

9*5 = 45

Kryger [21]3 years ago
5 0
The answer is that it takes Mary 45 minutes to run 9 laps.

Divide 40 minutes by 8 laps (40/8), which equals 5 minutes per 1 lap.

Now, multiply 5 minutes by 9 laps to get 45 minutes total.
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Step-by-step explanation:

just did the assignment on Delta Math

8 0
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Dmitriy789 [7]

Answer:

Step-by-step explanation:

Relative speed can play a major role in creating distance between two bodies. If the relative speed between two bodies is 0, then both the bodies are moving in the same direction with a similar speed. Thus, After 4 minutes, 1680 feet farther will Skateboarder B have traveled.

Skateboarder A travels at a steady rate of 15 feet per second.

Skateboarder B travels at a steady rate of 22 feet per second.

We need to determine that after 4 minutes, how much farther will Skateboarder B have traveled.

The formula for finding the distance travelled by anybody is represented below

Time is given that is 4 minutes which means 240 seconds.

Thus,

Distance travelled by skateboarder A

Distance travelled by skateboarder B.

Therefore, the separation of the distance between both the skateboarders is 5280 - 3600 = 1680.

Thus, After 4 minutes, 1680 feet farther will Skateboarder B have traveled.

7 0
2 years ago
The area of a rectangular patio is 3x2 + 17x + 20 ft
krek1111 [17]

Answer:

a

Step-by-step explanation:

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3 years ago
a woman 1.65. tall stood 50m away from the foot of a tower,and observe that the angle of elevation of the top of the tower to be
ElenaW [278]

\sf\huge\underline{\star Solution:-}

\rightarrowLet the women's height be AE and distance between the women and tower be AC.

Also let the height of tower be BC.

\rightarrowNow, clearly it is forming a triangle.

So, in triangle ABC,

\rightarrow\sf{Tan50° \:= \: \frac{BC}{AC}}

\rightarrow\sf{1.19 \:= \: \frac{BC}{50}}

\rightarrow\sf{1.19 ×50\:= \: BC}

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\rightarrowHence, BC = 59.5m

So, BD(total height of the tower)\sf{ = \:BC+CD}

\sf{= \:59.5+1.65}

\sf{=\: 61.15m}

Therefore, total height of the tower =\sf\purple{ 61.15m.}

________________________________

Hope it helps you:)

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Branilest and 30 point please answer
Lynna [10]

Answer:

<em>Addition Property of Equality</em>

Step-by-step explanation:

<u>System of Equations</u>

When two equations are given and two variables are unknown in both equations, then we can solve the system in several ways.

One method consists in adding both equations term by term and eliminate one of the variables. That property is called the addition of equalities. Let's consider the equations given in the problem:

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