The surface area of the triangular prism is 686.6 cm².
Step-by-step explanation:
Step 1:
The volume of a triangular prism can be determined by multiplying its area of the triangular base with the length of the prism.
The base triangle has a base length of 10 cm and assume it has a height of h m.
The volume of the prism
 
The height of the triangle is 8.66 cm.
Step 2:
The surface area of the triangle is obtained by adding all the areas of the shapes in the prism. There are 2 triangles and 3 rectangles in a triangular prism.
The triangles have a base length of 10 cm and a height of 8.66 cm. A triangles area is half the product of its base length and height.
The rectangles all have a length of 20 cm and a width of 10 cm. The area of a rectangle is the product of its length and width.
The area of the 2 triangles ![= 2 [\frac{1}{2} (10)(8.66)] = 86.6.](https://tex.z-dn.net/?f=%3D%202%20%5B%5Cfrac%7B1%7D%7B2%7D%20%2810%29%288.66%29%5D%20%3D%2086.6.)
The area of the 3 rectangle ![= 3[(20)(10)] = 600.](https://tex.z-dn.net/?f=%3D%203%5B%2820%29%2810%29%5D%20%3D%20600.)
Step 3:
The surface area of the triangular prism 
The surface area of the prism is 686.6 cm².
 
        
             
        
        
        
12 gallons = 96 us liquid pints.
        
             
        
        
        
Answer: 3/5
Step-by-step explanation: 1/5*3=1/5+1/5+1/5=3/5
 
        
             
        
        
        
Answer: 
Step-by-step explanation:
This car follows a line, hence its motion can be modeled by the Line equation.
In fact, we already have two points of the line, if we call 
 the time in hours and 
 the traveled distance in miles:
Point 1: 
Since we are told the car's initial position is 300 miles in the time 0 h
Point 2: 
Since we are told the car's final position is 180 miles after 3h
<u />
<u>Let's find the Slope 
:
</u>
  This is the slope of the line
Now, the equation of the line is:
We already know the slope, now we have to find the intersection point with the y-axis (
) with any of the given points. Let's choose Point 1: 
Isolating 
:
Then, the equation of the line is: