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3 years ago

Which equation in point-slope form contains the points (6,2) and (2,4)?

Mathematics

2 answers:

11111nata11111 [884]3 years ago

5 0

The slope is -1/2
y-2=-1/2(x-6)
OR
y-4=-1/2(x-2)

grandymaker [24]3 years ago

3 0

Answer:

y-2=-1/2(x-6)

or y-4=-1/2(x-2

Step-by-step explanation:

Trying 2 write a point slope equation with the given points.

The first step in getting a point slope equation, i.e. of the form (y-y1)=m(x-x1), is to find the slope.

m=(y2-y1)/(x2-x1)

m=(4-2)/(2-6)

m=2/-4=-1/2

Next, you plug in either of the points into the formula as (x1,y1).

The answer could have been either

y-2=-1/2(x-6)

or y-4=-1/2(x-2)

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creativ13 [48]

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Option C.

Step-by-step explanation:

Note : In the given points one point is (8,-2) instead of (-6,-2).

The standard form of a circle is

$(x-h)^2+(y-k)^2=r^2$

where, (h,k) is center of circle and r is radius.

It is given that center of the circle is (-1,-2). So,

$h=-1,k=-2$

$(x-(-1))^2+(y-(-2))^2=r^2$

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It is given that the circle passing through the point (8,-2),(-1,5),(6,-2),(-1,-9).

Substitute x=6 and y=-2 in equation (1).

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