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hram777 [196]
2 years ago
7

Consider a drug that is used to help prevent blood clots in certain patients. In clinical​ trials, among 5783 patients treated w

ith this​ drug, 153 developed the adverse reaction of nausea. Use a 0.05 significance level to test the claim that 3​% of users develop nausea. Does nausea appear to be a problematic adverse​ reaction?
Mathematics
1 answer:
Lubov Fominskaja [6]2 years ago
3 0

Answer:

Based on statistical analysis the claim is of 3% of patients developing adverse reaction is valid and there is a drug problem

Step-by-step explanation:

Here we have

Percentage of patients that develop nausea em= 153/5783 *100 = 2.65 %

To test the hypothesis, we put our null hypothesis as

H₀: μ = 3%

Alternative hypothesis is then

Hₐ: μ < 3%

Therefore the test statistic is

t=\frac{\hat{p}-p_0}{\sqrt{\frac{ p_0( 1- p_0)}{n}}}

P₀ = 0.03

\hat p = 0.0265

n = 5783

From the above we have our test statistic as -1.579 from which gives our p value as P = 0.057.

Therefore, as we have our P value less than the confidence level of 0.05, we therefore fail to reject the null hypothesis because there is sufficient statistical evidence that suggest that the proportion of patients who would have adverse reaction to the drug  = 3%.

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Find the equation of the line that passes through the points (-5,7) and (2,3)
Olegator [25]

Answer:

y=-\frac{4}{7}x+4\frac{1}{7}

Step-by-step explanation:

So, in order to solve this problem, I started off by drawing it out. On my graph that I have attached below, I first started out by locating the points (-5,7) and (2,3). Now, this is an optional step, but I highly encourage practicing your graphing skills by solving this problem on graph paper as well. Next, I connected the two points that I just graphed. This is the line that passes through (-5,7) and (2,3).

Now, here is where the actual solving starts. If you haven't already been taught this yet, I will introduce it to you now. I am going to find the equation of this line by filling in what I know in the equation y=mx+b, where m= the slope of the line, and b= y intercept.

Slope of the line: m= \frac{y_{1} - y_{2}  }{x_{1} - x_{2}  } = \frac{7-3}{-5-2} = \frac{4}{-7}= -\frac{4}{7}

If you haven't been taught how to find the slope of a line I recommend you find out.

Substitute the slope into the equation.

y=-\frac{4}{7} x+b\\

Now, we will solve for the 'b,' or y intercept.

We already have x and y values to use: (-5,7) or (2,3). I'll use x=2 and y=3 to solve for the y intercept.

y=-\frac{4}{7} x+b\\\\3=-\frac{4}{7} *2+b\\\\3=-\frac{8}{7} +b\\b=3+\frac{8}{7} \\b=\frac{21}{7}+\frac{8}{7}=\frac{29}{7} =4\frac{1}{7} \\b=4\frac{1}{7}

Last step: substitute the slope and y intercept into y=mx+b.

y=mx+b\\y=-\frac{4}{7}x+4\frac{1}{7}

That is the answer to this problem.

I hope this helps.

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