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3 years ago

Can someone plz help me solved this problem! I’m giving you 10 points! I need help plz help me! Will mark you as brainiest!

Mathematics

1 answer:

Kobotan [32]3 years ago

6 0

Answer: $2 or $9

Step-by-step explanation:

Revenue (R) = $1800 , x = 1100 - 100p

R = xp

1800 = (1100 - 100p)p substituted x with 1100 - 100p

1800 = 1100p - 100p² distributed p into 1100 - 100p

100p² - 1100p + 1800 = 0 added 100p² & subtracted 1100p on both sides

p² - 11p + 18 = 0 divided both sides by 100

(p - 2) (p - 9) = 0 factored quadratic equation

p = 2 p = 9 applied Zero Product Property to solve for p

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If x = 3 + 2√2, then the value of (x - 1/x) is a) 4√2 b) 2√4 c) 8

vitfil [10]

Your answer is: A. 4/2

Hope this helps and happy holidays!!

5 0

3 years ago

What does a zero slope line look like

nikdorinn [45]

It's a horizontal line

4 0

3 years ago

X-5+x-11=100 what is the reason for this statement for geometry?

Mariulka [41]

Answer:

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3 years ago

If an object is propelled upward from a height of s feet at an initial velocity of v feet per second, then its height h after t

Sergio039 [100]

From the given information we can write the equation:

-16t^2 +96t + 4 = 112

-16t^2 + 96t + 4 - 112 = 0

-16t^2 + 96t - 108 = 0

simplify, change the signs, divide by -4

4t^2 - 24t + 27 = 0

You can use the qudratic formula but this will factor to

(2t-3)(2t-9) = 0

Two solutions

t = 3/2

t = 1.5 seconds at 112 ft on the way up

and

t = 9/2

t = 4.5 seconds at 112 ft on the way back down

Graphically, (green line is 112 ft)

5 0

3 years ago

A student earned grades of 84, 78, 84, and 72 out of 100 on her four regular tests. She scored 78% on the final exam and 86% on

adelina 88 [10]

If the student received marks of 84, 78, 84, and 72 on her four normal tests, her weighted mean grade is 81.2 percent.

The mean is described as a single number that indicates either the closed value for each item in the collection of data or the mean value for the whole set of data.

On her four regular tests, a student had grades of 84, 78, 84, and 72 out of 100. She received 86 percent on her class projects and 78 percent on the final test.

You may compute the weighted mean as follows:

$\rm W_m= 0.4 \times ( \frac{84+78+84+72}{4} )+0.3 \times 78 +0.1 \times 86 + 0.2 \times 87 \\\\ W_m= 81.2 \%$

Hence, if the student had marks of 84, 78, 84, and 72 on her four normal tests, her weighted mean grade would be 81.2 percent.

To learn more about the mean refer;

brainly.com/question/22871228

#SPJ1

5 0

2 years ago