Answer:
The answer is cosx cot²x ⇒ the first answer
Step-by-step explanation:
∵ cot²x = cos²x/sin²x
∵ secx = 1/cosx
∴ cot²x secx - cosx = (cos²x/sin²x)(1/cosx) - cosx
= (cosx/sin²x) - cosx
Take cosx as a common factor
∴ cosx[(1/sin²x) - 1] ⇒ use L.C.M
∴ cosx[1-sin²x/sin²x]
∵ 1 - sin²x = cos²x
∴ cosx(cos²x/sin²x) = cosx cot²x
QUESTION:
n + 3 = -7
ANSWER:
STEP-BY-STEP EXPLANATION:
First, Subtract 3 from the both sides of the equation
Last, Subtract 3 from - 7
hope it's helps
Answer:
Step-by-step explanation:
Your problem setup is correct. The triangle is isosceles, so the marked segments are the same length.
3x - 8 = 2x
You can solve this by subtracting 2x (from both sides) ...
x - 8 = 0
Then adding 8 (to both sides):
x = 8
MB = MA = 2x = 16.
Answer:
x=17
Step-by-step explanation:
Answer:
Refer to the picture above
