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Amiraneli [1.4K]
3 years ago
11

Write an equation in slope-intercept form of the line that passes through (-1, 4) and (0,2). y =

Mathematics
1 answer:
telo118 [61]3 years ago
3 0

Answer:

y =( -1/2 )x + 2

Step-by-step explanation:

first step is to determine the slope of the line ( which is the rise over the run) or symbolically slope is defined as m= ∆x / ∆y, so plugging those values we get...

m= ∆x / ∆y = (-1 - 0) / (4 - 2) = -1 / 2

so next is to find the zero( y-intercept) of the function by ....

y = mx + b

y = ( -1/2)x + b (since m is equal to -1/2)

2 = ( -1/2)0 + b

2= b

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x+5+2x+3
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x+2x+5+3
=3x+8
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What is 15 1/5 + 3 5/8 ?
guajiro [1.7K]

The Answer is 750/40 = 18 33/40

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3 years ago
Guyss please help me with this question. I tried a thousand times but it's still incorrect.
Shalnov [3]

Answer: 17.68cm

Step-by-step explanation:

Using the area formula of a cone, find the height first.

A=\pi r(r+\sqrt{h^2+r^2})

Solve for h,

Begin by dividing by \pi r

\frac{A}{\pi r}=r+\sqrt{h^2+r^2}

Subtract r.

\frac{A}{\pi r}-r=\sqrt{h^2+r^2}

Square both sides.

(\frac{A}{\pi r}-r)^2=(\sqrt{h^2+r^2})^2

(\frac{A}{\pi r}-r)^2=h^2+r^2

Subtract r^2

(\frac{A}{\pi r}-r)^2-r^2=h^2

Extract the square root.

\sqrt{(\frac{A}{\pi r}-r)^2-r^2 } =\sqrt{h^2}

\sqrt{(\frac{A}{\pi r}-r)^2-r^2 } =h

Plug in your values.

\sqrt{[\frac{670cm^2}{(3.14)(8cm)}-(8cm)]^2-(8cm)^2 } =h

Solve;

\sqrt{[\frac{670cm^2}{25.12cm}-(8cm)]^2-(8cm)^2 } =h

\sqrt{[26.67cm-(8cm)]^2-(8cm)^2 } =h

\sqrt{(18.67cm)^2-(8cm)^2 } =h

\sqrt{348.57cm^2-64cm^2}=h

\sqrt{284.57cm^2}=h

15.77cm=h

------------------------------------------------------------------

Now, to find the slant height use this formula: l=\sqrt{h^2+r^2}

l=\sqrt{(15.77cm)^2+(8cm)^2}\\l=\sqrt{248.69cm^2+64cm^2}\\ l=\sqrt{312.69cm^2}\\ l=17.68cm

8 0
3 years ago
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