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3 years ago

Check my Geometry work?? Will give Brainliest

Mathematics

1 answer:

Travka [436]3 years ago

3 0

Answer:

in the step-by-step

Step-by-step explanation:

okay one thing is that you labelled wrong since you have to label D', D", D'" (you just labelled with one for all of them)

a you reflected across the y-axis wrong

-it would be that D' (-2,6), E' (-2,3), F' (-5,3)

b you rotated correctly

this gets more confusing since you labelled the triangles wrong, but I hope this first part helps

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Talja [164]

Answer: 5 is 2 and 1/2 6 is 2 and 3/4 7 is 3 and 4/5 8 is 10 and 1/2

Step-by-step explanation:

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5 0

2 years ago

Place

Anastaziya [24]

Answer:

$P(A\ and\ B) = \frac{3}{7}$

Step-by-step explanation:

<em>Your question is not well presented; (See Attachment for complete details)</em>

Required

Find P(A n B)

where

A = Event that the place is a city

B = Event that the place is in North

The first step is to get the sample space;

Let S represent the sample space;

$S = \{India,\ Tokyo,\ Houston,\ Peru,\ New York,\ Tijuana,\ Canada \}$

$n(S) = 7$

The next is to list events A and B

A = City

$A = \{Tokyo,\ Houston,\ New York,\ Tijuana\}$

B = North America

$B = \{Houston,\ New York,\ Tijuana,\ Canada\}$

The next is to list common elements in A and B

$A\ n\ B = \{Houston,\ New York,\ Tijuana\}$

$n(A\ and\ B) = 3$

The probability of A and B is calculated as follows;

$P(A\ and\ B) = \frac{n(A\ and\ B)}{n(S)}$

Substitute $n(A\ and\ B) = 3$ and $n(S) = 7$ in the expression above

$P(A\ and\ B) = \frac{3}{7}$

7 0

3 years ago

Find the slope given the following information <br> (3,7) and (-4,10)

hram777 [196]

Answer:

m=-3/7

Step-by-step explanation:

m=rise/run=Δy/Δx

m=y2−y1/x2−x1

m=10−7/−4−3

m=3/−7

m=−3/7

6 0

1 year ago

X^2 + 32x + 256 = 1<br>please show steps

Elena L [17]

$\boxed{x_{1}=-15} \\ \\ \boxed{x_{2}=-17}$

<h2>Explanation:</h2>

In this case, we have the following equation:

$x^2+32x+256=1$

But we can write this equation as:

$x^2+32x+256=1 \\ \\ Subtract \ -1 \ from\ both \ sides: \\ \\ x^2+32x+256-1=1-1 \\ \\ x^2+32x+255=0$

So this final result is a quadratic equation written in Standard Form ( $ax^2+bx+c=0$ ). We need to find the solutions to this equations, so let's use quadratic formula:

$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ a=1 \\ b=32 \\ c=255 \\ \\ \\ x=\frac{-32 \pm \sqrt{(32)^2-4(1)(255)}}{2(1)} \\ \\ x=\frac{-32 \pm \sqrt{1024-1020}}{2} \\ \\ x=\frac{-32 \pm \sqrt{4}}{2} \\ \\ x=\frac{-32 \pm 2}{2} \\ \\ Finally, \ two \ solutions: \\ \\ \boxed{x_{1}=-15} \\ \\ \boxed{x_{2}=-17}$