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3 years ago

5,-15,35,55.... What is the common difference

Mathematics

2 answers:

pogonyaev3 years ago

8 0

The common difference is -20! Person above is correct

harkovskaia [24]3 years ago

3 0

Answer:

The common difference is -20

Step-by-step explanation:

Simply subtract 5 from -15

-15-5 = -20

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Suppose that the pages per book in a library are normally distributed with an unknown mean and standard deviation. The book leng

Elanso [62]

Answer:

A t-score of 2.0244 should be used to find the 99% confidence interval for the population mean

Step-by-step explanation:

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 39 - 1 = 38

Now, we have to find a value of T, which is found looking at the t table, with 38 degrees of freedom(y-axis) and a confidence level of 0.99( $t_{99}$ ). So we have T = 2.0244.

A t-score of 2.0244 should be used to find the 99% confidence interval for the population mean

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3 years ago

Which linear function represents a slope of 1?

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3 years ago

Read 2 more answers

Six times a number +4 is the same as the number -11

FrozenT [24]

6x+4=-11
6x=-15
X=-15/6
X=-2.5

3 0

3 years ago

Select all systems that are equivalent to this system:

JulsSmile [24]

Answer:

can yhu see the answer i put?

Step-by-step explanation:

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2 years ago

Write a coordinate proof to prove that the segment that joins the vertex angle of an isosceles triangle to the midpoint of its b

Natalija [7]

Answer:

Slope of the base segment line is zero, hence base segment is horizontal

Slope of the segment that joins the vertex angle to the midpoint of its base is undefined hence the line is vertical

Therefore, angle between base segment line and the segment line from the vertex angle to the midpoint is perpendicular

Therefore, the segment that joins the vertex angle to an isosceles triangle to the midpoint of its base is perpendicular to the base

Step-by-step explanation:

Here we prove the required relation as follows;

Let the isosceles be ABC

The coordinates of the points are

C = (0, 0) (Vertex)

A = (-a, b)

C = (a, b)

P = (0, b) (Midpoint of base)

Therefore, the gradient or slope of the base AC is presented as follows;

$Slope, m \, of \. base, \, AC= \frac{dy}{dx} = \frac{b - b}{a - (-a)} = \frac{0}{2\cdot a} = 0$

Hence, segment AC is vertical

$Slope, m \, of \, segment \ CP \, joining \, vertex, \, to \, midpoint, P, on \,AC = \frac{0 - b}{0 - 0} = \frac{-b}{0} = Undifined.$

Hence, segment CP is vertical

Therefore, the segment that joins the vertex angle to an isosceles triangle to the midpoint of its base is perpendicular to the base.

6 0

3 years ago