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2 years ago

5,-15,35,55.... What is the common difference

Mathematics

2 answers:

pogonyaev2 years ago

8 0

The common difference is -20! Person above is correct

harkovskaia [24]2 years ago

3 0

Answer:

The common difference is -20

Step-by-step explanation:

Simply subtract 5 from -15

-15-5 = -20

You might be interested in

Find the approximate perimeter of ABC plotted below.

maksim [4K]

Answer:

B. 21.2

Step-by-step explanation:

Perimeter of ∆ABC = AB + BC + AC

A(-4, 1)

B(-2, 3)

C(3, -4)

✔️Distance between A(-4, 1) and B(-2, 3):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$AB = \sqrt{(-2 - (-4))^2 + (3 - 1)^2} = \sqrt{(2)^2 + (2)^2)}$

$AB = \sqrt{4 + 4}$

$AB = \sqrt{16}$

AB = 4 units

✔️Distance between B(-2, 3) and C(3, -4):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$BC = \sqrt{(3 - (-2))^2 + (-4 - 3)^2} = \sqrt{(5)^2 + (-7)^2)}$

$BC = \sqrt{25 + 49}$

$BC = \sqrt{74}$

BC = 8.6 units (nearest tenth)

✔️Distance between A(-4, 1) and C(3, -4):

$AC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$AC = \sqrt{(3 - (-4))^2 + (-4 - 1)^2} = \sqrt{(7)^2 + (-5)^2)}$

$AC = \sqrt{47 + 25}$

$AC = \sqrt{74}$

AC = 8.6 units (nearest tenth)

Perimeter of ∆ABC = 4 + 8.6 + 8.6 = 21.2 units

8 0

3 years ago

I am lost on what to do

Neko [114]

$\bf sin({{ \alpha}})sin({{ \beta}})=\cfrac{1}{2}[cos({{ \alpha}}-{{ \beta}})\quad -\quad cos({{ \alpha}}+{{ \beta}})]
\\\\\\
cot(\theta)=\cfrac{cos(\theta)}{sin(\theta)}\\\\
-----------------------------\\\\
\lim\limits_{x\to 0}\ \cfrac{sin(11x)}{cot(5x)}\\\\
-----------------------------\\\\
\cfrac{sin(11x)}{\frac{cos(5x)}{sin(5x)}}\implies \cfrac{sin(11x)}{1}\cdot \cfrac{sin(5x)}{cos(5x)}\implies \cfrac{sin(11x)sin(5x)}{cos(5x)}$

$\bf \cfrac{\frac{cos(11x-5x)-cos(11x+5x)}{2}}{cos(5x)}\implies \cfrac{\frac{cos(6x)-cos(16x)}{2}}{cos(5x)}
\\\\\\
\cfrac{cos(6x)-cos(16x)}{2}\cdot \cfrac{1}{cos(5x)}\implies \cfrac{cos(6x)-cos(16x)}{2cos(5x)}
\\\\\\
\lim\limits_{x\to 0}\ \cfrac{cos(6x)-cos(16x)}{2cos(5x)}\implies \cfrac{1-1}{2\cdot 1}\implies \cfrac{0}{2}\implies 0$

4 0

3 years ago

A bicycle tire has a radius of 10 inches. To the nearest inch, how far does the tire travel when it makes 4 revolutions?

Aloiza [94]

Answer: 251.2 inches.

Step-by-step explanation: You have to multiply 4*2*π*radius. So, simply multiply 4*2*3.14*10. It would come out as 251.2 inches.

6 0

2 years ago

A large diamond with a mass of 481.3 grams was recently discovered in a mine. If the density of the diamond is 3.51 , what is th

sineoko [7]

Answer:

137.12

Step-by-step explanation:

Density = mass/volume

Density = 3.51

Mass = 481.3

Thus: 481.3/3.51 = 137.122507123

6 0

3 years ago

Read 2 more answers

Jill cuts a piece of cardboard in the shape of a trapezoid.The area of the is 43.5sp cm. If bases are cm and 8.5cm long,what is

boyakko [2]

Answer:

7.25cm

Step-by-step explanation:

Let the complete question be;

<em>Jill cuts a piece of cardboard in the shape of a trapezoid. The area of the is 43.5sp cm. If bases are 3.5cm and 8.5cm long, what is the height.</em>

<em />

Area of a trapezoid = 1/2(a+b)*h

a and b are the parallel sides (bases)

h is the height

Given

a = 3.5cm

b = 8.5cm

A = 43.5 sq.cm

Required

Height h

Substitute the given values into the expression

Area of a trapezoid = 1/2(a+b)*h

43.5 = 1/2(3.5+8.5)*h

43.5 = 1/2 * 12h

43.5 = 6h

h = 43.5/6

h = 7.25cm

Hence the height is 7.25cm

8 0

3 years ago