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3 years ago

The quotient of a number and 9 is equal to the same number decreased by 40. what is the number

1 answer:

7 0

Quotient is the result of dividing two numbers.

x= the unknown number

The equation is x divided by 9 equals x minus 40.

x/9= x - 40
multiply both sides by 9

(9)(x/9)= (9)(x - 40)
x= 9x - 360

subtract 9x from both sides
-8x= -360

divide both sides by -8
x= 45

ANSWER: The number is 45.

Hops this helps! :)

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Need some help with this math problem

Makovka662 [10]

Answer:

probably t=40-3h cause of simple math if you don't understand I suggest using khan academy

3 0

2 years ago

Elimination_4x_2y=14 _10x+7y=_24

Gnesinka [82]

Answer:

The answer is $x=-\frac{50}{8}$ and $y=\frac{11}{2}.$

Step-by-step explanation:

Given:

-4x-2y=14

-10x+7y=-24

Now, to solve it by elimination:

$-4x-2y=14$ ......(1)

$-10x+7y=-24$ ......(2)

So, we multiply the equation (1) by 7 we get:

$-28x-14y=98$

And, we multiply the equation (2) by 2 we get:

$-20x+14y=-48$

Now, adding both the new equations:

$-28x-14y+(-20x+14y)=98+(-48)$

$-28x-14y-20x+14y=98-48$

$-28x-20x-14y+14y=50$

$-8x=50$

Dividing both the sides by -8 we get:

$x=-\frac{50}{8}$

Now, putting the value of $x$ in equation (1):

$-4x-2y=14$

$-4(-\frac{50}{8})-2y=14$

$\frac{200}{8} -2y=14$

$25-2y=14$

Subtracting both sides by 25 we get:

$-2y=-11$

Dividing both sides by -2 we get:

$y=\frac{11}{2}$

Therefore, the answer is $x=-\frac{50}{8}$ and $y=\frac{11}{2}.$

5 0

3 years ago

The student council is selling tickets to a school dance. One teacher decides to pay $10 for his class, and the students in the

Lostsunrise [7]

Hi,

x + y = 350 (equation 1)

3x + 2y = 950 (equation 2)

Use Substitution Method

Isolate variable x in equation 1

x = 350 – y (equation 3)

Substitute equation 3 into equation 2

3(350 – y) + 2y = 950

1050 – 3y + 2y = 950

3y – 2y = 1050 – 950

y = 100

Substitute y = 100 into equation 1

x + 100 = 350

x = 250

Answer: 250 $3 tickets and 100 $2 tickets were sold.

8 0

3 years ago

Find the equation of all tangent lines having slope of -1 that are tangent to the curve y=(9)/(x+1)

fredd [130]

Answer:

$f(x)=\frac9{x+1}\\ f'(x)=-\frac9{(x+1)^2}\\ f'(x)=-1\ \iff\ -\frac9{(x+1)^2}=-1\ \to \ \frac9{(x+1)^2}=1\ \to \ (x+1)^2=9\\ |x+1|=3\ \to \ x+1=3\ \vee\ x+1=-3\\ x_1=2\ \vee\ x_2=-4\\ f(x_1)=f(2)=\frac9{2+1}=3\\ f(x_2)=f(-4)=\frac9{-4+1}=-3$