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umka21 [38]
3 years ago
5

Part 1 out of 2 A patio in the shape of a rectangle , is fenced on all sides with 94 feet of fencing . The patio is 7 feet less

wide than it is long. I feet ( -7 feet What information can be used to solve the problem ? How can you find the information ? You need the select and select of the patio . You can write algebraic expressions for the length and width Use the expressions in the formula for the ( select ) rectangle , and then solve to find the length and the width .

Mathematics
1 answer:
polet [3.4K]3 years ago
4 0

Answer:

  length, width, perimeter

Step-by-step explanation:

First of all, you should notice that <em>no problem is posed</em>. A description is given, but no question is asked about it.

_____

If we assume that the length and width of the patio are desired, then those are the selections for the first two boxes.

The only other characteristic of the situation that is provided is the <em>perimeter</em>. So the formula for perimeter is the only one that can be usefully used.

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Which is perpendicular to the line y=-3x-8y
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I believe the answer is y = -7/3x

Step-by-step explanation:

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Sketch the domain D bounded by y = x^2, y = (1/2)x^2, and y=6x. Use a change of variables with the map x = uv, y = u^2 (for u ?
cluponka [151]

Under the given transformation, the Jacobian and its determinant are

\begin{cases}x=uv\\y=u^2\end{cases}\implies J=\begin{bmatrix}v&u\\2u&0\end{bmatrix}\implies|\det J|=2u^2

so that

\displaystyle\iint_D\frac{\mathrm dx\,\mathrm dy}y=\iint_{D'}\frac{2u^2}{u^2}\,\mathrm du\,\mathrm dv=2\iint_{D'}\mathrm du\,\mathrm dv

where D' is the region D transformed into the u-v plane. The remaining integral is the twice the area of D'.

Now, the integral over D is

\displaystyle\iint_D\frac{\mathrm dx\,\mathrm dy}y=\left\{\int_0^6\int_{x^2/2}^{x^2}+\int_6^{12}\int_{x^2/2}^{6x}\right\}\frac{\mathrm dx\,\mathrm dy}y

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We require that u>0, and the last equation tells us that we would also need v>0. This means 1\le v\le\sqrt2 and 0, so that the integral over D' is

\displaystyle2\iint_{D'}\mathrm du\,\mathrm dv=2\int_1^{\sqrt2}\int_0^{6v}\mathrm du\,\mathrm dv=\boxed6

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