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3 years ago

The table shows the gallons filled in a pool over time (ASAP)

Mathematics

1 answer:

satela [25.4K]3 years ago

5 0

Answer:

125, 250, 500, 625

Step-by-step explanation:

As you can see, half of the pool is 500. 2 halves would make a whole, concluding the pool is 1000. Then for the 1/8, do 1000/8. Getting 125. 1000/4 would make it 250. And then taking the 125 from the earlier division of 8 and multiplying by 5 will get you 625. Hope this helps <3

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Reuben is making a replica of the US flag for his school project.

Leno4ka [110]

P1=2.5+2.5+4.75+4.75=14.5 cm

0.5 cm - 1 in
2.5 cm - 5 in
4.75 cm - 9.5 in

P2=5+5+9.5+9.5=29 in

8 0

3 years ago

Hi, can someone help with these two questions ASAP! (Ignore the multiple choice I circled, not sure if it’s correct)

Sindrei [870]

Answer:

1) D. $y = -\frac{3}{2}\cdot x^{12} -7\cdot x^{5}+\frac{2}{3}\cdot x -10$

2) E. The coefficient of $x$ is -16.

Step-by-step explanation:

1) A polynomial is an algebraic expression of the form $p(x) = \Sigma \limits_{i = 0}^{n} c_{i}\cdot x^{i}$ , where $n$ is the grade of the polynomial. In this case, the only equation that satisfies this definition is:

$y = -\frac{3}{2}\cdot x^{12} -7\cdot x^{5}+\frac{2}{3}\cdot x -10$

Correct answer: D

2) Let $p(x) = (2\cdot x + 1) \cdot (5\cdot x^{3}-8\cdot x +4)$ , we proceed to expand the expression by algebraic means:

$p(x) = (2\cdot x + 1)\cdot (5\cdot x^{3}) -(2\cdot x +1)\cdot (8\cdot x) + 4\cdot (2\cdot x + 1)$

$p(x) = 10\cdot x^{4}+5\cdot x^{3}-16\cdot x^{2}+4$

We see that coefficients for $x^{2}$ and $x$ are -16 and 0, respectively. Hence, the incorrect answer is E.

3 0

3 years ago

Was a major accomplishment of both Tutankhamun and Rameses II. Plz help

LenKa [72]

Answer:

AA similarity. The angles in both are the same.

Edit: I don't know if you need this, but a major accomplishment of King Tut and Ramses was that they encouraged the following of ancient religious beliefs among the Egyptian people .

Hope that this helps!

6 0

3 years ago

What is the exact area and arc length of these sectors? Please helppp

Karolina [17]

Answers with step-by-step explanation:

1. Area of sector 1 = $\frac{90}{360} \times \pi \times 12^2 = 36\pi$

2. Area of sector 2 = $\frac{45}{360} \times \pi \times 19^2 = \frac{2527}{8} \pi$

3. Area of sector 3 = $\frac{270}{360} \times \pi \times 15^2 = \frac{675}{4} \pi$

4. Area of sector 4 = $\frac{270}{360} \times \pi \times 6^2 = 27 \pi$

5. Arc length of sector 1 = $\frac{90}{360} \times 2 \times \pi \times 12 = 6\pi$

6. Arc length of sector 2 = $\frac{315}{360} \times 2 \times \pi \times 19 = \frac{133}{4} \pi$

7. Arc length of sector 3 = $\frac{270}{360} \times 2 \times \pi \times 15 = \frac{45}{2}\pi$

8. Arc length of sector 4 = $\frac{270}{360} \times 2 \times \pi \times 6 = 9\pi$

4 0

3 years ago

ASAP please top to bottom is 384,691,2073,1038 all pi cm3

Korvikt [17]

V...volume
B...Base
h...height

V=1/3 × B × h
V=1/3 ×r^2×pi × h
V=1/3 ×12^2×pi × 8
V= 1/3 ×144×pi ×8
V=1/3 × 1152pi
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4 0

3 years ago