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3 years ago

What is the equation of a line, in Slope Intercept Form, with a slope of 4 and passes through the point (1, 6)?

Mathematics

1 answer:

Butoxors [25]3 years ago

5 0

The slope-intercept form:

$y=mx+b$

m - slope

b - y-intercept

We have the slope m = 4 → $y=4x+b$

and point (1, 6). Substitute:

$6=4(1)+b$

$6=4+b$ <em>subtract 4 from both sides</em>

$2=b\to b=2$

<h3>Answer: y = 4x + 2</h3>

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$= (3y ^ 6 + 4) + (9y ^ {12} - 12y ^ 6 + 16)\\= (3y ^ 6 + 4) + (9y ^ {12} - 12y ^ 6 + 16)\\collect \ like \ terms\\= 9y^{12} +3y^6 - 12y^6 + 16+ 4\\= 9y^{12} - 9y^6 + 20\\$

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Using a plus (-) sign to check:

$= (3y ^ 6 + 4) - (9y ^ {12} - 12y ^ 6 + 16)\\= 3y ^ 6 + 4 - 9y ^ {12} + 12y ^ 6 - 16\\collect \ like \ terms\\= -9y^{12} +3y^6 +12y^6 + 4-16\\= -9y^{12} +15y^6 -12\\$

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