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3 years ago

Help plz6(2x - 11) + 15 = 3x + 12

Mathematics

2 answers:

Ket [755]3 years ago

3 0

Answer:

x = 7

Step-by-step explanation:

Lets do the brackets first,

6 × 2x = 12

6 × -11 = -66

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Calculate the x constant:

12x - 3x = 9x

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Then the ones with no x:

-66 + 15 = -51

51 + 12 = 63

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Lastly, divide

63 ÷ 9 = 7

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Have a good day :)

marusya05 [52]3 years ago

3 0

X = 7

hope this helps you out!

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Simplify: -|-15| please answer correctly i'll give brainliest and 5-star rating.

12345 [234]

Answer:

-15

Step-by-step explanation:

Definition of absolute value:

Distance from zero on a number line.

Imagine a number line with 0 in the middle of it. Now mark the number 3 on it. Also mark the opposite of 3, which is -3. What is the distance from zero to those 2 points? it's 3.

This is exactly like saying |3| = 3 and |-3| = 3

Even if the number inside absolute value is negative, it simplifies to the positive of the same number.

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So let's talk about your problem.

-|-15|

> the absolute value simplifies to 15

-|-15| = - 15

So that ends up being your answer.

$-15$

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3 years ago

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Ierofanga [76]

Step-by-step explanation:

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3 years ago

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zlopas [31]

Answer:

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Step-by-step explanation:

Just by analyzing the problem you can match up the answers

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3 years ago

Read 2 more answers

If 10 servings are 4 ounces how many ounces is 7 servings

gregori [183]

Answer:

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Step-by-step explanation:

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2 years ago

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A ball is thrown into the air and its position is given by h ( t ) = − 6.3 t 2 + 53 t + 24 where h is the height of the ball in

nordsb [41]

Answer:

$h'(t) = -12.6 t +53$

Now we can set up the derivate equal to 0 and we have:

$-12.6 t +53 = 0$

And solving for t we got:

$t = \frac{53}{12.6}= 4.206$

For the second derivate respect the time we got:

$h''(t) = -12.6$

So then we can conclude that t = 4.206 is a maximum for the function.

And the corresponding height would be:

$h(t=4.206) = -6.3(4.206)^2 +53*4.206+24= 135.468 ft$

So the maximum occurs at t = 4.206 s and with a height of 135.468 m

Step-by-step explanation:

For this case we have the following function:

$h(t) = -6.3t^2 +53 t+24$

In order to maximize this function we need to take the first derivate respect the time and we have:

$h'(t) = -12.6 t +53$

Now we can set up the derivate equal to 0 and we have:

$-12.6 t +53 = 0$

And solving for t we got:

$t = \frac{53}{12.6}= 4.206$

For the second derivate respect the time we got:

$h''(t) = -12.6$

So then we can conclude that t = 4.206 is a maximum for the function.

And the corresponding height would be:

$h(t=4.206) = -6.3(4.206)^2 +53*4.206+24= 135.468 ft$

So the maximum occurs at t = 4.206 s and with a height of 135.468 m

8 0

4 years ago

Help plz6(2x - 11) + 15 = 3x + 12​

Help plz6(2x - 11) + 15 = 3x + 12