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3 years ago

If a person earns $19,850 per year , estimate that persons hourly salary ..please give me details and how you rounded

1 answer:

4 0

There is 24 hours in a day and 365 days in an average year so 24 × 365=8760 hours in a year so its 19850/8760 which is equal to 2.265... so if the digit is 5 or higher u raise the next to up 1 if its 4 keep the next number the same so in this case ur answer is about 2.27 dollars

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mixas84 [53]

Answer:

0.375

Step-by-step explanation:

Convert the fraction to a decimal by dividing the numerator by the denominator.

3/8 = 0.375

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2 years ago

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2 years ago

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Angelina_Jolie [31]

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3 years ago

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Andru [333]

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Step-by-step explanation:

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2 years ago

A consumer survey indicates that the average household spendsμ= $185on groceries each week. The distribution of spending amounts

Vitek1552 [10]

Answer:

$P(X>200)=P(\frac{X-\mu}{\sigma}>\frac{200-\mu}{\sigma})=P(Z>\frac{200-185}{25})=P(Z>0.6)$

And we can find this probability using the complement rule and with the normal standard table or excel:

$P(Z>0.6)=1-P(z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the average household spent of a population, and for this case we know the distribution for X is given by:

$X \sim N(185,25)$

Where $\mu=185$ and $\sigma=25$

We are interested on this probability

$P(X>200)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X>200)=P(\frac{X-\mu}{\sigma}>\frac{200-\mu}{\sigma})=P(Z>\frac{200-185}{25})=P(Z>0.6)$

And we can find this probability using the complement rule and with the normal standard table or excel:

$P(Z>0.6)=1-P(z$

7 0

2 years ago