Answer:
The voltage across resistor is 
Step-by-step explanation:
We are given with Voltage across terminals of a series RL circuit, 
And Resistance R=40Ω
And inductor reactance 
Ω
Since Resistor and inductor are in series, same current flows through both.
And that current, I = 
= 
Therefore voltage across resistor, 
Answer:
9
Step-by-step explanation:
1.1x+1.2x-5.4=-10x
Move all terms to the left:
1.1x+1.2x-5.4-(-10x)=0
Add all the numbers together, and all the variables
2.3x-(-10x)-5.4=0
Get rid of parentheses
2.3x+10x-5.4=0
Add all the numbers together, and all the variables
12.3x-5.4=0
Move all terms containing x to the left, all other terms to the right
12.3x=5.4
x=5.4/12.3
x=3.8571428571429/8.7857142857143
Hope it helps!
Let the lengths of the bottom of the box be x and y, and let the length of the squares being cu be z, then
V = xyz . . . (1)
2z + x = 16 => x = 16 - 2z . . . (2)
2z + y = 30 => y = 30 - 2z . . . (3)
Putting (2) and (3) into (1) gives:
V = (16 - 2z)(30 - 2z)z = z(480 - 32z - 60z + 4z^2) = z(480 - 92z + 4z^2) = 480z - 92z^2 + 4z^3
For maximum volume, dV/dz = 0
dV/dz = 480 - 184z + 12z^2 = 0
3z^2 - 46z + 120 = 0
z = 3 1/3 inches
Therefore, for maximum volume, a square of length 3 1/3 (3.33) inches should be cut out from each corner of the cardboard.
The maximum volume is 725 25/27 (725.9) cubic inches.
8/6 = 12/9
8/6 x 9/9 = 72/54
12/9 x 6/6 = 72/54
72/54 = 72/54
They are similar.
Triangle ABC is similar to triangle PQR
