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Reil [10]
3 years ago
12

I need to know the proper way to solve this

Mathematics
1 answer:
ahrayia [7]3 years ago
8 0
Divide both sides by -6:
(u+5) ^{2} =-20

Then take the square root of both sides and subtract
5u=-5+i \sqrt{20}

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What is the area of the 3.1 by 1.4 rectangle?
uranmaximum [27]

Answer: 4.34

Step-by-step explanation:

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I need this answer in 30 minutes please help !!<br> **WILL MARK THE FIRST PERSON BRAINLIEST**
Brrunno [24]
Y=-1/2x+5 slope=-1/2 because it goes down one unit and to the right 2 units, and the y intercept is 5 because that's where the line intercepts the y-axis!
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3 years ago
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A student is given that point P(a, b) lies on the terminal ray of angle Theta, which is between StartFraction 3 pi Over 2 EndFra
Harman [31]

Answer:

<em>A.</em>

<em>The student made an error in step 3 because a is positive in Quadrant IV; therefore, </em>

<em />cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}

Step-by-step explanation:

Given

P\ (a,b)

r = \± \sqrt{(a)^2 + (b)^2}

cos\theta = \frac{-a}{\sqrt{a^2 + b^2}} = -\frac{\sqrt{a^2 + b^2}}{a^2 + b^2}

Required

Where and which error did the student make

Given that the angle is in the 4th quadrant;

The value of r is positive, a is positive but b is negative;

Hence;

r = \sqrt{(a)^2 + (b)^2}

Since a belongs to the x axis and b belongs to the y axis;

cos\theta is calculated as thus

cos\theta = \frac{a}{r}

Substitute r = \sqrt{(a)^2 + (b)^2}

cos\theta = \frac{a}{\sqrt{(a)^2 + (b)^2}}

cos\theta = \frac{a}{\sqrt{a^2 + b^2}}

Rationalize the denominator

cos\theta = \frac{a}{\sqrt{a^2 + b^2}} * \frac{\sqrt{a^2 + b^2}}{\sqrt{a^2 + b^2}}

cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}

So, from the list of given options;

<em>The student's mistake is that a is positive in quadrant iv and his error is in step 3</em>

3 0
3 years ago
Write the number 164 in expanded form
Lapatulllka [165]
If you were to write 164 in expanded form, it would be 100 + 60 + 4 = 164
Hope this helps and can I get brainliest answer bc i need it to rank up!! :D
7 0
3 years ago
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PLESE HELP YOU WILL GET ALOT OF POINTS
Vedmedyk [2.9K]

Answer:

It's a <em>(space) </em>lot<em>,... </em>haha na I just kidding,... you're good,... I mean I'm not kidding cause it is correct,... but you are good,... like totally cool,... anyway,...

Step-by-step explanation:

By x the just mean <em>what number,... </em>so,...

<em>what number </em>+ 6 = 7,

6 + <em>what number = 7,</em>

2 + <em>what number </em>+ 5 = 7,

1 + <em>what number</em> = 7,

<em>what number </em>+ 4 + <em>what number </em> = 7,

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<em />

4 0
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