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Pavlova-9 [17]
3 years ago
13

A game require rolling a six sided die numbered fro 1 to 6. What is the probability of rolling a 1 or a 2?

Mathematics
1 answer:
Virty [35]3 years ago
8 0

Answer:

1/3

Step-by-step explanation:

hello,

probability of 1 = 1/6

probability of 2 = 1/6

probability of 1 or 2 = 1/6+1/6 as probability of 1 and 2 = 0

so the answer is 2/6=1/3

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The object will hit the ground after 5 seconds. You can rewrite the quadratic function as a quadratic equation set equal to zero
mario62 [17]

Answer:

289

Step-by-step explanation:

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3 years ago
What is 21,678 rounded to the nearest ten
prohojiy [21]

Answer:

21,678 rounded to the nearest ten is 21,680

5 0
3 years ago
Use compatible numbers to estimate the quotient 2,545÷4
victus00 [196]

Answer:

600

Step-by-step explanation:

round 2,545 to 2,400 and keep 4 the same because 24 goes into 4 six times so 2400/4 equals 600  

24/4 is 6 and you add the two zeros

3 0
3 years ago
Use implicit differentiation to find the points where the parabola defined by x2−2xy+y2+4x−8y+20=0 has horizontal and vertical t
Komok [63]

Answer:

The parabola has a horizontal tangent line at the point (2,4)

The parabola has a vertical tangent line at the point (1,5)

Step-by-step explanation:

Ir order to perform the implicit differentiation, you have to differentiate with respect to x. Then, you have to use the conditions for horizontal and vertical tangent lines.

-To obtain horizontal tangent lines, the condition is:

\frac{dy}{dx}=0 (The slope is zero)

--To obtain vertical tangent lines, the condition is:

\frac{dy}{dx}=\frac{1}{0} (The slope is undefined, therefore the denominator is set to zero)

Derivating respect to x:

\frac{d(x^{2}-2xy+y^{2}+4x-8y+20)}{dx} = \frac{d(x^{2})}{dx}-2\frac{d(xy)}{dx}+\frac{d(y^{2})}{dx}+4\frac{dx}{dx}-8\frac{dy}{dx}+\frac{d(20)}{dx}=2x -2(y+x\frac{dy}{dx})+2y\frac{dy}{dx}+4-8\frac{dy}{dx}= 0

Solving for dy/dx:

\frac{dy}{dx}(-2x+2y-8)=-2x+2y-4\\\frac{dy}{dx}=\frac{2y-2x-4}{2y-2x-8}

Applying the first conditon (slope is zero)

\frac{2y-2x-4}{2y-2x-8}=0\\2y-2x-4=0

Solving for y (Adding 2x+4, dividing by 2)

y=x+2 (I)

Replacing (I) in the given equation:

x^{2}-2x(x+2)+(x+2)^{2}+4x-8(x+2)+20=0\\x^{2}-2x^{2}-4x+x^{2} +4x+4+4x-8x-16+20=0\\-4x+8=0\\x=2

Replacing it in (I)

y=(2)+2

y=4

Therefore, the parabola has a horizontal tangent line at the point (2,4)

Applying the second condition (slope is undefined where denominator is zero)

2y-2x-8=0

Adding 2x+8 both sides and dividing by 2:

y=x+4(II)

Replacing (II) in the given equation:

x^{2}-2x(x+4)+(x+4)^{2}+4x-8(x+4)+20=0\\x^{2}-2x^{2}-8x+x^{2}+8x+16+4x-8x-32+20=0\\-4x+4=0\\x=1

Replacing it in (II)

y=1+4

y=5

The parabola has vertical tangent lines at the point (1,5)

4 0
3 years ago
Find the maximum value of the function f(x) = -1.9x^2 + 24x – 71.3 to the<br> nearest hundredth.
d1i1m1o1n [39]
Being that the system is quadratic—with parabola opening downwards—you’re going to need to find the vertex. You can find the x coordinate of the vertex with -b/2a . Then plug in for x to find the y coordinate…
4 0
2 years ago
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