All categories

3 years ago

If f (x) = 4x - 11 , What is the value of f(5) a. 20x - 55 b. 34 c. 9 d. 4

Mathematics

1 answer:

kramer3 years ago

5 0

Answer:C

Step-by-step explanation:

You might be interested in

Tyron has 27 playlists on his iPod. Each playlist contains 35 songs. How many songs does Tyron have on all of his playlists?

xeze [42]

Answer:

945 songs

Step-by-step explanation:

27*35=945

4 0

3 years ago

Using the distributive property to factorize the equation 3x^2+24x=0, you get

Natalka [10]

Answer:

Step-by-step explanation:

$3x^2+24x=0\\factor: 3x(x+8)=0\\x=0, -8$

6 0

2 years ago

Read 2 more answers

Would the answer be 19 1/3 or 1? Please help!

zhannawk [14.2K]

Answer:

19 because it greater and im guessing

8 0

2 years ago

Macy wants to sell her old Playstation 4 games on decluttr.com. The wtbsite charges sellers a comission of 20%

muminat

Answer:

$28

Step-by-step explanation:

The website charges 20%, so Macy receives 80%.

Then:

80% x 35=.8 x 35=28 ....................

5 0

3 years ago

(5x^3-8x^2+9x+12)/(x-3)<br><br> please answer with sentences on how to do it step by step. thanks!

Anastaziya [24]

Answer:

$5x^2+7x+30+\frac{102}{x-3}$

Step-by-step explanation:

$\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}5x^3-8x^2+9x+12\\\mathrm{and\:the\:divisor\:}x-3\mathrm{\::\:}\frac{5x^3}{x}=5x^2\\\mathrm{Quotient}=5x^2\\\mathrm{Multiply\:}x-3\mathrm{\:by\:}5x^2:\:5x^3-15x^2\\\mathrm{Subtract\:}5x^3-15x^2\mathrm{\:from\:}5x^3-8x^2+9x+12\mathrm{\:to\:get\:new\:remainder}\\\mathrm{Remainder}=7x^2+9x+12\\\mathrm{Therefore}\\=5x^2+\frac{7x^2+9x+12}{x-3}$

$\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}7x^2+9x+12\\\mathrm{and\:the\:divisor\:}x-3\mathrm{\::\:}\frac{7x^2}{x}=7x\\\mathrm{Quotient}=7x\\\mathrm{Multiply\:}x-3\mathrm{\:by\:}7x:\:7x^2-21x\\\mathrm{Subtract\:}7x^2-21x\mathrm{\:from\:}7x^2+9x+12\mathrm{\:to\:get\:new\:remainder}\\\mathrm{Remainder}=30x+12\\\mathrm{Therefore}\\=5x^2+7x+\frac{30x+12}{x-3}\\$

$\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}30x+12\\\mathrm{and\:the\:divisor\:}x-3\mathrm{\::\:}\frac{30x}{x}=30\\\mathrm{Quotient}=30\\\mathrm{Multiply\:}x-3\mathrm{\:by\:}30:\:30x-90\\\mathrm{Subtract\:}30x-90\mathrm{\:from\:}30x+12\mathrm{\:to\:get\:new\:remainder}\\\mathrm{Remainder}=102\\\mathrm{Therefore}\\=5x^2+7x+30+\frac{102}{x-3}$

6 0

2 years ago

Read 2 more answers