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Brums [2.3K]
3 years ago
15

How can properties be used to generate equivalent expressions?

Mathematics
1 answer:
vesna_86 [32]3 years ago
6 0
T<span>he student is able to apply the Distributive Property to expand the expression but not to factor it.




</span>
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What is the equation, in slope-intercept form, of the line that is perpendicular to the line y – 4 = –Two-thirds(x – 6) and pass
Fantom [35]

The equation is y = Three-halvesx + 1

Step-by-step explanation:

That line should be perpendicular to the given line : y-4 = -2/3 (x-6) and

It passes through (-2,-2)

Write the equation in slope-intercept form as;

y-4= -2/3 (x-6)

y-4=-2/3x + 4

y= -2/3x + 8

The slope m₁, of the equation is -2/3

For perpendicular lines, m₁*m₂= -1

So,finding m₂ where m₁ = -2/3

-2/3 * m₂ = -1

m₂ = -1 * - 3/2 = 3/2

The equation of the line passing through point (-2,-2) with m₂=3/2 will be;

y--2/x--2 = 3/2

y+2/x+2=3/2

2(y+2)=3(x+2)

2y+4=3x+6

2y=3x+6-4

2y=3x+2

y=3/2x +1  ⇒⇒Three-halves *x+1

Learn More

Equation of perpendicular lines : brainly.com/question/11482954

Keyword : equation, slope-intercept form, perpendicular

#LearnwithBrainly

6 0
3 years ago
Read 2 more answers
Find the valve of X and Y . Can i get with work out please
Solnce55 [7]

Step-by-step explanation:

on line AB

X + 117 = 180 ( Angle sum property )

X = 63°

and

X+Y = 90° (given )

63° + Y = 90°

Y = 27°

3 0
3 years ago
Read 2 more answers
Please help me with these
Alex Ar [27]
When we approach limits, we are finding values that are infinitesimally approaching this x-value. Essentially, we consider the approximate location that this root or limit appears. This is essential when it comes to taking Calculus, and finding the limit or rate of change of a function.

When we are attempting limits questions, there are several tests we attempt first.

1. Evaluate the limit by substituting the value of the x-value as it approaches the value (direct evaluation of a limit)
2. Rearrangement of the function, such that we can evaluate the limit.
3. (TRIGONOMETRIC PROPERTIES)
\lim_{x \to 0} (\frac{sinx}{x}) = 1
\lim_{x \to 0} (\frac{tanx}{x}) = 1
4. Using L'Hopital's Rule for indeterminate limits, such as 0/0, -infinity/infinity, or infinity/infinity.

For example:

1) \lim_{x \to 0}\frac{\sqrt{x} - 5}{x - 25}

We can do this using the first and second method.
<em>Method 1: Direct evaluation:</em>

Substitute x = 0 to the function.
\frac{\sqrt{0} - 5}{0 - 25}
= \frac{-5}{-25}
= \frac{1}{5}

<em>Method 2: Rearranging the function
</em>

We can see that x - 25 can be rewritten as: (√x - 5)(√x + 5)
By rewriting it in this form, the top will cancel with the bottom easily, and our limit comes out the same.

\lim_{x \to 0}\frac{(\sqrt{x} - 5)}{(\sqrt{x} - 5)(\sqrt{x} + 5)}
= \lim_{x \to 0}\frac{1}{(\sqrt{x} + 5)}}
= \frac{1}{5}

Every example works exactly the same way, and by remembering these criteria, every limit question should come out pretty naturally.
8 0
3 years ago
The zeroes of the polynomial f(x) = x^2+x+3/4 are​
matrenka [14]

Step-by-step explanation:

f(x) = x² + x + 3/4

in general, such a quadratic function is defined as

f(x) = a×x² + b×x + c

the solution for finding the values of x where a quadratic function value is 0 (there are as many solutions as the highest exponent of x, so 2 here in our case)

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case

a = 1

b = 1

c = 3/4

x = (-1 ± sqrt(1² - 4×1×3/4))/(2×1) =

= (-1 ± sqrt(1 - 3))/2 = (-1 ± sqrt(-2))/2 =

= (-1 ± sqrt(2)i)/2

x1 = (-1 + sqrt(2)i) / 2

x2 = (-1 - sqrt(2)i) / 2

remember, i = sqrt(-1)

f(x) has no 0 results for x = real numbers.

for the solution we need to use imaginary numbers.

6 0
3 years ago
Read 2 more answers
Write an equation of the line with slope 2/3 that goes through the point -2,5
irinina [24]

Answer:

y = 2/3x + 19/3

Step-by-step explanation:

First, this is your current equation: y = 2/3x + b. Plug in your point to the equation, it should look like this: 5 = 2/3(-2) + b. 2/3 times -2 equals -4/3. So, this is what your equation should look like: 5 = -4/3 + b. Add 4/3 to both sides of the equation to get 19/3 = b. Go back to your original equation and plug 19/3 to b. This is your final equation: y = 2/3x + 19/3. Hope this helped!

7 0
3 years ago
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