Answer:
a) I donot agree with him because as we see the sequence nicely we will find an interval of 8 between any two terms and 32 and 33 don't match them
Step-by-step explanation:
b) and c) Solution:
Given,
First term (a) = 4
Common difference (d) = 12-4 = 8
Now,
Since, they are in A.P.
nth term = a + (n-1)d
= 4 + 8(n-1)
= 4 + 8n-8
= 8n-4
Again,
1st method for c)
100th term = a + 99d = 4 + 99*8 = 4 + 792 = 796
200th term = a + 199d = 4 + 199*8 = 4 + 1592 = 1596
2nd method for c)
100th term = 8*100 - 4 = 800 - 4 = 796
200th term = 8*200 - 4 = 1600 - 4 = 1596
Answer:
x=23
Step-by-step explanation:
Answer:
You should <u>carry 2 other batteries.</u>
Step-by-step explanation:
If the average life of each battery tends to last 6.9 months, and what you need is a year of battery supply, you probably need to carry two batteries.
The battery inside the flashlight has probably already spent much of its half-life.
We are told that the flashlight already has a battery inside, the batteries are discharged inside the flashlight even if the flashlight is not being used.
Which means that the average life of that battery is wearing out.
It would take 2 more batteries in addition to the one already inside the flashlight to supply the need for these for a year.
The sine ratio is basically a fraction of the opposite side over the hypotenuse. Since the hypotenuse is always the longest side, this means the fraction cannot exceed 1. If it did,then that would lead to the opposite side being larger than the hypotenuse but again the hypotenuse is the longest side. The largest the sine ratio can get is 1.
