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sasho [114]
2 years ago
9

Which values are solutions of the inequality 5 < y -88 , 9. , 13. , 15. , 20

Mathematics
1 answer:
Sladkaya [172]2 years ago
6 0

Answer:

5 is greater than y-8 since 5 is positive it + in the begging +5 while - 8 is less than 0 because it has - in the begging

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The following polynomial is defined on the interval [-2, 2]:
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Answer:

Using Matlab code for Fourier series to calculate for the function, see the attached

Step-by-step explanation:

Go through the picture step by step.

6 0
3 years ago
Enter the equivalent distance in km in the box.
FinnZ [79.3K]

Answer:

3.5 kilometers

Step-by-step explanation:

35000/100 = 3500

3500/1000=3.5

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3 years ago
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Please Help Me!!!!!! I have a big test tomorrow!!!!!!!! I will give 30 points!!!!!!!!! The expression represents the number of m
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For this expression I guessed I would use subtraction because when you subtract Kimiko's miles to Celeste's miles you could see how much faster Kimiko was than Celeste.

Step-by-step explanation:

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2 years ago
A sample of 11 students using a Ti-89 calculator averaged 31.5 items identified, with a standard deviation of 8.35. A sample of
lina2011 [118]

Answer:

We reject H₀, with CI = 90 % we can conclude that the mean numbers of times identified with Ti-84 does not exceed that of the Ti-89 by more than 1,80

Step-by-step explanation:

Ti-89 Calculator

Sample mean     x = 31,5

Sample standard deviation   s₂  = 8,35

Sample size        n₂ = 11

Ti-84 Calculator

Sample mean     y = 46,2

Sample standard deviation   s₁  = 9,99

Sample size        n₁ = 12

t(s)  = ( y - x - d ) / √s₁²/n₁ + s₂²/n₂

t(s)  = 12,9 / √(99,8/12) + (69,72/11)

t(s)  = 12,9 / √8,32 + 6,34

t(s)  = 12,9 / 3,83

t(s) = 3,37

Test Hypothesis

Null Hypothesis               H₀      y - x > 1,80

Altenative Hypothesis       Hₐ      y - x ≤ 1,80

We have a t(s) = 3,37

We need to compare with t(c)   critical value for

t(c) α; n₁ +n₂-2            df = 12 +11 -2     df  = 21

If we choose  CI = 95 %    then  α = 5 %   α = 0,05

From t-student table

t(c) = 1,72

t(s) = 3,37

t(s) >t(c)

t(s) is in the rejection region therefore we accept Hₐ with CI = 95 %

8 0
3 years ago
Suppose f is a function with exponential growth and f(0)=1. Explain why f can be represented by a formula of the form
galben [10]

We are supposed to explain why the given function can be expressed in form f(x)=b^{x}, when f(0)=1.

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Now let us substitute x=0 in the given function,  

f(x)=b^{x}

f(0)=b^{0}  

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Let us substitute x=0 in our function.    

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f(0)=a  

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f(x) = 1(b)^{x}

f(x) =(b)^{x}

Therefore, our function f can be represented by the formula of the form f(x)=b^{x}.

7 0
3 years ago
Read 2 more answers
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