Larger is x
the other is called y
sum of squares is 394
x^2+y^2=394
one is 2 less that other
x>y so
y+2=x
subsitute y+2 for x
(y+2)^2+y^2=394
expand
y^2+4y+4+y^2=394
add like terms
2y^2+4y+4=394
divideboth sides by 2
y^2+2y+2=197
subtract 197 from both sides
y^2+2y-195=0
factor
(y+15)(y-13)=0
set each to zero
y+15=0
y=-15
impossible since it is stated that they are positive so get rid of this solution
y-13=0
y=13
find other
y+2=x
13+2=x
15=x
numbers are 13 and 15
Well the answer is 43.86, but if it is asking for an estimate you’d prolly round to either 40 or 45. hope this helps
Answer:
4.6
Step-by-step explanation:
x³-6x=72
x³-6x-72=0 .... a solution between 4 and 5
x=4 x³-6x-72= 64-24-72 = -32
x=5 x³-6x-72= 125-30-72 = 23
we have to find an x value that makes x³-6x-72 --> 0
see the attachment, we can find the 0 value of x is between 4.63 and 4.64
‘to 1 decimal place’ of the solution is: 4.6 (4.63 is too small and 4.64 is too big)