Look at the picture.
1)|AM| = |MB| = x
|AN| = |NC| = y
|BC| = 2y - 2x = 2(y - x)
|MN| = y - x
Therefore |BC| = 2|MN|
2)|AM| = |MB| = x
|AN| = |NC| = y
|BC| = 2y - 2x = 2(y - x)
|MN| = y - x
Therefore |BC| = 2|MN|
354 / 4 = 88.5
so2 numbers below that and 2 numbers above that:
87 + 88 + 89 +90 =
2nd number is 88
Answer:
Pythagoras’ theorem is a way to find a side or hypothesis when you have 2 sides.
The formula is: a^2 + b^2 = c^2
a and b are sides
c is the hypothesis
<u>Ex: A triangle has a leg that is 5 inches and a leg that is 7 inches. Find the hypothesis using Pythagoras' theorem. </u>
A leg is another way of saying a side.
5^2 + 7^2 = c^2
25 + 49 = x^2
sqrt(74) = sqrt(x^2)
sqrt(74) inches = hypothesis
<u>Ex: A triangle has a leg that is 9 feet and a hypothesis that is 25 feet. Find the other leg using Pythagoras' theorem. </u>
9^2 + b^2 = 25^2
81 + b^2 - 81 = 625 - 81
sqrt(b^2) = sqrt(544)
b = sqrt(554)
Do you understand more?
Answer:
36.50
To two decimal places
Step-by-step explanation:
The hypothenuse side in a right angle triangle has 58cm. While the angle touching one of its leg is 51°. How long is that leg.
From the right angled triangle, the size of the leg touching the hypothenuse is the adjacent side of the triangle, hence in trigonometry, the cosine rule is used, because it involves the adjacent and the hypotenuse.
Cos 51°=x/58
Let the size of the leg be x
Making x the subject
x=58(Cos51°)
x=36.500058
Correct to two decimal place
x=36.50
This is a typical radioactive decay problem which uses the general form:
A = A0e^(-kt)
So, in the given equation, A0 = 192 and k = 0.015. We are to find the amount of substance left after t = 55 years. That would be represented by A. The solution is as follows:
A = 192e^(-0.015*55)
<em>A = 84 mg</em>
