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artcher [175]
2 years ago
5

A garden measuring 12 meters by 6 meters is going to have a walkway constructed all around the perimeter, increasing the total a

rea to 160 square meters. What will be the width of the pathway? (The pathway will be the same width around the entire garden).
Mathematics
2 answers:
damaskus [11]2 years ago
4 0

Answer:

x=2

Step-by-step explanation:

Original width = 6

New width 6+x+x

Orignal length 12

New length  12+x+x

A = l*w

160 = ( 6+2x) ( 12+2x)

Factor

160 = 2( 3+x) 2(6+x)

Divide each side by 4

40 = (3+x) (6+x)

FOIL

40 = 18+ 6x+3x+ x^2

40 = 18 +9x+x^2

Subtract 40 from each side

0 = x^2 +9x -22

Factor

0 = (x +11) (x-2)

Using the zero product property

x +11 =0   x-2 =0

x= -11   x=2

Since we cannot have a negative  sidewalk

x =2

Paraphin [41]2 years ago
3 0

Answer:

2

Step-by-step explanation:

Original width = 6

New width = 6 + x + x = 6 + 2x

Orignal length = 12

New length = 12 + x + x = 12 + 2x

A = l * w

160 = (6 + 2x)(12 + 2x)

160 = 2(3+x) * 2(6+x)

160 = 4 * (3 + x)(6 + x)

160/4 = (3 + x)(6 + x)

40 = 18 + 6x + 3x + x^2

40 = 18 + 9x + x^2

x^2 + 9x - 22 = 0

= x^2 + 11x - 2x - 22 = 0

= x(x + 11) - 2(x + 11) = 0    

= (x + 11) (x - 2) = 0

x = - 11, 2

Since we cannot have a negative width because it's a dimension,

x = 2 is right

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