How much is 3/4 cup & 3/4 cup =
2 answers:
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Missing data:
Viewer's Age Group Excellent Good Average Poor Marginal Total
16–25 52 42 12 7 113
26–35 33 50 5 9 97
36–45 58 12 28 34 132
46–55 25 17 22 12 76
56 + 12 5 3 8 28
Marginal Total 180 126 70 70 446
A rating of good or excellent indicates the audience liked the movie, while a rating of poor indicates the audience disliked the movie.
<h3>How to determine the rating of the film from the 46–55 age group?</h3>A movie producer accomplished a survey behind a preview screening of her latest movie to estimate how the film would be accepted by viewers from various age groups. The table displays the numbers of viewers in various age groups who ranked the film excellent, good, average, and poor.
25/446 = 0.05605
0.05605 100% = 5.605%
Out of the entire respondents, the percentage of respondents from the 46–55 age group who ranked the film excellent exists at 5.605%.
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Answer:
20)
19)
18)
17)
16)
15)
14)
13)
12)
11)
Step-by-step explanation:
20) {−2x - y = −9
{5x - 2y = 18
⅖[5x - 2y = 18]
{−2x - y = −9
{2x - ⅘y = 7⅕ >> New Equation
__________
[Plug this back into both equations above to get the x-coordinate of 4];
_______________________________________________
19) {−5x - 8y = 17
{2x - 7y = −17
−⅞[−5x - 8y = 17]
{4⅜x + 7y = −14⅞ >> New Equation
{2x - 7y = −17
_____________
[Plug this back into both equations above to get the y-coordinate of 1];
_______________________________________________
18) {−2x + 6y = 6
{−7x + 8y = −5
−¾[−7x + 8y = −5]
{−2x + 6y = 6
{5¼x - 6y = 3¾ >> New Equation
____________
[Plug this back into both equations above to get the y-coordinate of 2];
_______________________________________________
17) {−3x - 4y = 2
{3x + 3y = −3
__________
[Plug this back into both equations above to get the x-coordinate of −2];
_______________________________________________
16) {2x + y = 20
{6x - 5y = 12
−⅓[6x - 5y = 12]
{2x + y = 20
{−2x + 1⅔y = −4 >> New Equation
____________
[Plug this back into both equations above to get the x-coordinate of 7];
_______________________________________________
15) {6x + 6y = −6
{5x + y = −13
−⅚[6x + 6y = −6]
{−5x - 5y = 5 >> New Equation
{5x + y = −13
_________
[Plug this back into both equations above to get the x-coordinate of −3];
_______________________________________________
14) {−3x + 3y = 3
{−5x + y = 13
−⅓[−3x + 3y = 3]
{x - y = −1 >> New Equation
{−5x + y = 13
_________
[Plug this back into both equations above to get the y-coordinate of −2];
_______________________________________________
13) {−3x + 3y = 4
{−x + y = 3
−⅓[−3x + 3y = 4]
{x - y = −1⅓ >> New Equation
{−x + y = 3
________
_______________________________________________
12) {−3x - 8y = 20
{−5x + y = 19
⅛[−3x - 8y = 20]
{−⅜x - y = 2½ >> New Equation
{−5x + y = 19
__________
[Plug this back into both equations above to get the y-coordinate of −1];
_______________________________________________
11) {x + 3y = 1
{−3x - 3y = −15
___________
[Plug this back into both equations above to get the y-coordinate of −2];
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