If you notice the picture below, the amount of fencing, or perimeter, that will be used will be 3w + 2l
now
![\bf \begin{cases} A=l\cdot w\\\\\ A=3000000\\ ----------\\ 3000000=l\cdot w\\\\ \frac{3000000}{w}=l \end{cases}\qquad thus \\\\\\ P=3w+2l\implies P=3w+2\left( \cfrac{3000000}{w} \right)\implies P=3w+\cfrac{6000000}{w} \\\\\\ P=3w+6000000w^{-1}\\\\ -----------------------------\\\\ now\qquad \cfrac{dP}{dw}=3-\cfrac{6000000}{w^2}\implies \cfrac{dP}{dw}=\cfrac{3w^2-6000000}{w^2} \\\\\\ \textit{so the critical points are at } \begin{cases} 0=w^2\\\\ 0=\frac{3w^2-6000000}{w^2} \end{cases}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Bcases%7D%0AA%3Dl%5Ccdot%20w%5C%5C%5C%5C%5C%0AA%3D3000000%5C%5C%0A----------%5C%5C%0A3000000%3Dl%5Ccdot%20w%5C%5C%5C%5C%0A%5Cfrac%7B3000000%7D%7Bw%7D%3Dl%0A%5Cend%7Bcases%7D%5Cqquad%20thus%0A%5C%5C%5C%5C%5C%5C%0AP%3D3w%2B2l%5Cimplies%20P%3D3w%2B2%5Cleft%28%20%5Ccfrac%7B3000000%7D%7Bw%7D%20%5Cright%29%5Cimplies%20P%3D3w%2B%5Ccfrac%7B6000000%7D%7Bw%7D%0A%5C%5C%5C%5C%5C%5C%0AP%3D3w%2B6000000w%5E%7B-1%7D%5C%5C%5C%5C%0A-----------------------------%5C%5C%5C%5C%0Anow%5Cqquad%20%5Ccfrac%7BdP%7D%7Bdw%7D%3D3-%5Ccfrac%7B6000000%7D%7Bw%5E2%7D%5Cimplies%20%5Ccfrac%7BdP%7D%7Bdw%7D%3D%5Ccfrac%7B3w%5E2-6000000%7D%7Bw%5E2%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Ctextit%7Bso%20the%20critical%20points%20are%20at%20%7D%0A%5Cbegin%7Bcases%7D%0A0%3Dw%5E2%5C%5C%5C%5C%0A0%3D%5Cfrac%7B3w%5E2-6000000%7D%7Bw%5E2%7D%0A%5Cend%7Bcases%7D)
solve for "w", to see what critical points you get, and then run a first-derivative test on them, for the minimum
notice the
![0=w^2\implies 0=w](https://tex.z-dn.net/?f=0%3Dw%5E2%5Cimplies%200%3Dw)
so. you can pretty much skip that one, though is a valid critical point, the width can't clearly be 0
so.. check the critical points on the other
Answer:
-5/7
Step-by-step explanation:
remember slope is eqaul to rise over run.
6-11 = -5 so it rose down by 5 units
10 - 3 = 7 so it ran 7 units
thus
slope= -5/7
Answer:
25
Step-by-step explanation:
un carro tiene 4 ruedas, entonces divide 100 por 4
100÷4=25
N - 7 = 9 if you want it written in equation form
multiply the hourly rate by number of hours worked
12.75 x 35.25 = 449.44 per week
449.44 x 2 = 898.88 for two weeks