There's the positive term- Strong, Elite.

A school has 636 boys. The numbers of girls at the school is 58 less than the number of boys. How many boys and girls are at the

dezoksy [38]

636 + 636 - 58 = 636 + 578
= 1214 kids

8 0

3 years ago

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Construc t a 95% confidence interval for the population standard deviation σ of a random sample of 15 men who have a mean weight

GrogVix [38]

The 95% confidence interval for the population standard deviation will be,

$$\sqrt{\frac{(n-1) s^{2}}{\chi^{2}} \frac{\alpha}{2}} & < \sigma < \sqrt{\frac{(n-1) s^{2}}{\chi^{2}}} \\$

simplifying the equation, we get

$$\sqrt{\frac{2551.5}{26.1}} & < \sigma < \sqrt{\frac{2551.5}{5.63}} \\9.887 & < \sigma < 21.288$

The 95% confidence interval exists (9.887, 21.288).

<h3>What is the 95% of confidence interval?</h3>

A random sample of 15 men exists selected. The mean weight exists at $165.2 pounds and the standard deviation exists at $13.5 pounds. The population exists normally distributed.

So, $n=15, \bar{X}=165.2, s=13.5$

where n exists the sample size, $\bar{X}$ exists the sample size

s exists the sample standard deviation.

The degrees of freedom will be n - 1 i.e.15 - 1 = 14.

For a 95% confidence interval, the level of significance will be $\alpha=0.05$ .

The 95% confidence interval for the population standard deviation will be,

$$\sqrt{\frac{(n-1) s^{2}}{\chi^{2}} \frac{\alpha}{2}} & < \sigma < \sqrt{\frac{(n-1) s^{2}}{\chi^{2}}} \\$

substitute the values in the above equation, we get

$$\sqrt{\frac{(15-1)(13.5)^{2}}{\chi^{2}} 0.05} & < \sigma < \sqrt{\frac{(15-1)(13.5)^{2}}{\chi_{0}^{2}}} \\$

$$\sqrt{\frac{(15-1)(13.5)^{2}}{\chi_{0.975}^{2}}} & < \sigma < \sqrt{\frac{(15-1)(13.5)^{2}}{\chi_{0.025}^{2}}} \\$

simplifying the above equation, we get

$$\sqrt{\frac{2551.5}{26.1}} & < \sigma < \sqrt{\frac{2551.5}{5.63}} \\9.887 & < \sigma < 21.288$

The 95% confidence interval exists (9.887, 21.288).

To learn more about confidence interval refer to:

brainly.com/question/14825274

#SPJ4

6 0

2 years ago

Test the claim that the proportion of men who own cats is smaller than the proportion of women who own cats at the .10 significa

nata0808 [166]

Answer:

The test statistics is $t = -1.40$

The critical value is $Z_{\alpha } = 2.33$

The null hypothesis is rejected

Step-by-step explanation:

From the question we are told that

The sample size for men is $n_1 = 80$

The sample proportion of men that own a cat is $\r p _M = 0.40$

The sample size for women is $n_2 = 80$

The sample proportion of women that own a cat is $\r p_F = 0.51$

The level of significance is $\alpha = 0.10$

The null hypothesis is $H_o : \r p _M = \ r P_F$

The alternative hypothesis is $H_a : \r p _M < \r p_F$

Generally the test statistic is mathematically represented as

$t = \frac{(\r p_M - \r p_F)}{\sqrt{\frac{(p_M*(1-p_M)}{n_1 } } + \frac{p_F*(1-pF)}{n_2 } }$

=> $t = \frac{(0.40 - 0.51)}{\sqrt{\frac{(0.40 *(1-0.41)}{80} } + \frac{0.51*(1-0.51)}{80 } }$

=> $t = -1.40$

The critical value of $\alpha$ from the normal distribution table is

$Z_{\alpha } = 2.33$

The p-value is obtained from the z-table ,the value is

$p-value = P( Z < -1.40) = 0.080757$

=> $p-value = 0.080757$

Given that the $p-value < \alpha$ then we reject the null hypothesis

7 0

3 years ago

The chase club at a school has 15 members the number of games won are listed what measures of center is most appropriate to use

olga_2 [115]

11-12 is the most center

4 0

3 years ago

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HELP ASAP !!

masya89 [10]

Answer:

$y$

Step-by-step explanation:

The graph in the attached figure

<em>Find the equation of the dashed line</em>

we have

points (0,2) and (5,3)

<em>Find the slope</em>

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

substitute the given values

$m=\frac{3-2}{5-0}$

$m=\frac{1}{5}$

<em>Find the equation of the dashed line in slope intercept form</em>

$y=mx+b$

we have

$m=\frac{1}{5}$

$b=2$

substitute

$y=\frac{1}{5}x+2$

Remember that

The solution of the inequality is the shaded area below the dashed line

therefore

The equation of the inequality is

$y$

3 0

3 years ago