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IrinaK [193]
3 years ago
10

HCF and LCM of (1-x^2)(1-y^2)+4xy,1-2xy+y-x^2y+x^2​

Mathematics
1 answer:
professor190 [17]3 years ago
7 0

Answer:

x2(y2 - 1) Now by using the identity a2 - b2. x2(y2 - 12) = x2(y + 1) (y - 1) Also, factorizing xy2 - 2xy - 3x by taking the common factor 'x' we get, x(y2 - 2y -

Step-by-step explanation:

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Answer:

\huge\boxed{\sf x = 16.3}

Step-by-step explanation:

Firstly we've to find the hypotenuse of the first triangle:

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\rule[225]{225}{2}

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