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4 years ago

9

IN WHICH SET OF ORDERED PAIRS IS Y A FUNCTION OF X ? A.(1.25,6) (3,6) (5.75,6) (11,6) B.(2,15) (3,12) (4,10) (4,8) C.(6,1) (3,8)

(3,9) (6,12) D.(6.5,10) (6.5,0) (6.5,9) (6.5,12)

1 answer:

ElenaW [278]4 years ago

6 0

Answer:

b is the answer

Step-by-step explanation:

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Use the figure to complete the statements.

Eddi Din [679]

Answer:

16

10

160

Step-by-step explanation:

The base also known as the right space is 16 because its labeled!

The height is also Labeled as 10.

Now all you have to do is 10 x 16 which equals 160!

Sorry I'm late!

3 0

3 years ago

Cleo wants to jion a gym. There is an initiation fee of $24.99, and each month of membership costs $12.50. If Cleo pays $174.99,

mamaluj [8]

Answer: The membership will last for 12 months.

Step-by-step explanation:

Let x represent the number of months that the membership would last.

Cleo wants to join a gym. There is an initiation fee of $24.99, and each month of membership costs $12.50. This means that the total cost of using the gym for x months would be expressed as

12.5x + 24.99

If Cleo pays $174.99, it means that

12.5x + 24.99 = 174.99

12.5x = 174.99 - 24.99

12.5x = 150

x = 150/12.5

x = 12

6 0

3 years ago

Determine the measure of each numbered angle. Show work, provide a brief explanation.

monitta

Huhvgujvdthb friend gf t if y h iutzyreRx it’s g. Ttussuesru. G h

5 0

2 years ago

X squared+ y squared = 2 y = 2x squared – 3 Which of the following describes the system?

cluponka [151]

Answer:

$x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}$ and $y=-1,\frac{1}{2}$

The ordered pair solutions are $(-\sqrt{\frac{7}{4}},0.5)$ , $(\sqrt{\frac{7}{4}},0.5)$ , $(-1,-1)$ , and $(1,-1)$ .

Step-by-step explanation:

I'm assuming the system is $\left \{ {x^2+y^2=2} \atop {y=2x^2-3}} \right.$ :

$x^2+y^2=2$

$x^2+(2x^2-3)^2=2$

$x^2+(4x^4-12x^2+9)=2$

$x^2+4x^4-12x^2+9=2$

$4x^4-11x^2+9=2$

$4x^4-11x^2+7=0$

$x^4-11x^2+28=0$

$(x^2-7)(x^2-4)=0$

$(4x^2-7)(x^2-1)=0$

$4x^2-7=0$

$4x^2=7$

$x^2=\frac{7}{4}$

$x=\pm\sqrt{\frac{7}{4}}$

$x^2-1=0$

$x^2=1$

$x=\pm1$

$y=2x^2-3$

$y=2(\pm\sqrt{\frac{7}{4}})^2-3$

$y=2({\frac{7}{4}})-3$

$y=\frac{7}{2}-3$

$y=\frac{1}{2}$

$y=2x^2-3$

$y=2(\pm1)^2-3$

$y=2(1)-3$

$y=2-3$

$y=-1$

Therefore, $x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}$ and $y=-1,\frac{1}{2}$

The ordered pair solutions are $(-\sqrt{\frac{7}{4}},0.5)$ , $(\sqrt{\frac{7}{4}},0.5)$ , $(-1,-1)$ , and $(1,-1)$ .

4 0

2 years ago

If I can walk 9673.6 meters in 5 hours. How far can I walk in 70 minutes. ( I need the work)

den301095 [7]

First, convert 5 hours into minutes:

5 hours 60 min

------------ * --------------- = 300 min

1 1 hr

Next, find the unit rate in m/min:

9673.6 m

--------------- = 32.24 m/min

300 min

Now find the distance you can walk in 70 minutes at this rate:

32.24 m

------------- * 70 min = 2247 meters (answer)

1 min

You could walk 2247 meters (to the nearest meter) in 70 minutes.

6 0

3 years ago