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Ahat [919]
3 years ago
9

IN WHICH SET OF ORDERED PAIRS IS Y A FUNCTION OF X ? A.(1.25,6) (3,6) (5.75,6) (11,6) B.(2,15) (3,12) (4,10) (4,8) C.(6,1) (3,8)

(3,9) (6,12) D.(6.5,10) (6.5,0) (6.5,9) (6.5,12)
Mathematics
1 answer:
ElenaW [278]3 years ago
6 0

Answer:

b is the answer

Step-by-step explanation:

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(-6x3-4x2-8)+(x3-x2-9x+4) add together and simply
Aleksandr [31]

Answer:

-5x³ -5x² -9x - 4

Step-by-step explanation:

(-6x³-4x²-8)+(x³-x²-9x+4)

Add the like terms.

-6x³ and x³ are like terms. -6x³ + x³ = -5x³

-4x² and -x² are like terms. -4x² - x² = -5x²

-8 and 4 are like terms. -8 + 4 = -4

-6x³-4x²-8 +x³-x²-9x+4 = -5x³ -5x² -9x - 4

6 0
3 years ago
If you can drive 32 miles on one gallon of gas how many miles can you drive on 20 gallons?
Veseljchak [2.6K]

Answer:

640

Step-by-step explanation:

32 *20

4 0
3 years ago
1.3.33 Question Help A certain triangle has a perimeter of 3078 mi. The shortest side measures 71 mi less than the middle side,
maksim [4K]

Answer:

the shortest side is 855 miles long.

Step-by-step explanation:

a + b + c = 3078 miles

a = b - 71

c = b + 371

=>

(b-71) + b + (b+371) = 3078

3b + 300 = 3078

3b = 2778

b = 926 miles

a = 926 - 71 = 855 miles

c = 926 + 371 = 1297 miles

8 0
3 years ago
The officers of a high school senior class are planning to rent buses and vans for a class trip. Each bus can transport 6363 ​st
attashe74 [19]

Answer:

  • 1 bus, 72 vans
  • $6960 is the minimum cost

Step-by-step explanation:

A bus costs over $19 per student; a van costs less than $12 per student. The required number of students could be transported by 81 vans, but that requires 81 chaperones.

Since there are only 80, and a bus requires fewer chaperones per student, we can reduce the number of required chaperones to an acceptable level by employing one bus. 1 bus replaces 9 vans, and requires 1 less chaperone than 9 vans.

The minimum cost is 1 bus and 72 vans. That cost is $1200 +72×$80 = $6960.

3 0
3 years ago
A standard deck of 52 cards contains 4 suits: hearts, clubs, diamonds, and spades. Each suit contains cards numbered 2 through 1
Vesnalui [34]

Answer:

2 / 13

Step-by-step explanation:

Number of cards in a standard deck = 52

Number of 4's = 4 ( 1 for each suit)

Number of 6's = 4 (1 for each suit)

Probability, P = required outcome / Total possible outcomes

P(a 4) = 4 / 52 = 1/ 13

P(a 6) = 4 /52 = 1/13

Probability of either a 4 or a 6

P(a 4) + P(a 6)

1/13 + 1/13

= 2 / 13

3 0
3 years ago
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