Let student tickets be s and adult tickets be a. The number of tickets sold of both adult and student then is s + a = 396. If each student ticket costs $3, then we represent the money equation by tacking the dollar amount onto the ticket. 3s is the cost of one student ticket. 4a is the cost of an adult ticket. The total money from the sales of both is 4a + 3s = 1385. We now have a system of equations we can solve for a and s. If s+a=396, then s = 396-a. We will sub that into the second equation to get 4a + 3(396-a) = 1385. Distributing we have 4a+1188-3a=1385. a = 197. That means there were 197 adult tickets sold. If s + a = 396, then s + 197 = 396 and s = 199. 197 adult tickets and 199 student tickets. There you go!
The answer is: A
Cause I had this test before and I aced it ;)
<h2><em>If you put and label the three points in a line, you will see that RS + ST = RT.
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</em></h2><h2><em>Then you only need to substitue with the expressions given for RS and ST to find RT.
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</em></h2><h2><em>RT = x +1 + 2x - 2 = 3x - 1
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</em></h2><h2><em>Also, RT = 5x - 5
</em></h2><h2><em>
</em></h2><h2><em>Then, 3x - 1 = 5x - 5
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</em></h2><h2><em>5x - 3x = 5 - 1
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</em></h2><h2><em>2x = 4
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</em></h2><h2><em>x = 4/2 = 2
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</em></h2><h2><u><em>X=2</em></u></h2>
Answer:
3
Step-by-step explanation:
Period of a function is the period after which the function attains the same value
in the graph attached with this problem we can see that
f(0)=1
the value of x for which function f(x) attains the value 1 again is at
x=3
f(3)=1
similarly , we see
f(6)=1 , f(9)=1
Hence we see that after every increased value of x by 3 units , we attain the same value of function . hence the period of the function is 3
