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Tatiana [17]
3 years ago
14

I need help with this question

Mathematics
2 answers:
tia_tia [17]3 years ago
8 0
26.5 goes in the first box
The answer is 689.
djverab [1.8K]3 years ago
6 0

Answer:

26.5 and 689

Step-by-step explanation:

A=b x h

A= 26.5 x 26

A=689ft

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Fill in the blanks.<br><br> (x+_)^2=x^2+14x+_
Serga [27]

Step-by-step explanation:

(ax + b)² = a²x² + 2abx + b²

In this case, a = 1, so:

14 = 2b

b = 7

(x + 7)² = x² + 14x + 49

7 0
3 years ago
Simplify to create an equivalent expression.<br> 2-4(5p+1)}2−4(5p+1)
ZanzabumX [31]

Answer:

-8-60p

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
What does the value of y have to be so that<br> (3, y) and (-5,6) have a slope of -1 between them?
Natasha_Volkova [10]

Answer:

y= -2

Step-by-step explanation:

Please see attached picture for full solution.

(From the 4th to 5th line, I multiplied both sides by 8)

3 0
3 years ago
If sinA=√3-1/2√2,then prove that cos2A=√3/2 prove that
Ivan

Answer:

\boxed{\sf cos2A =\dfrac{\sqrt3}{2}}

Step-by-step explanation:

Here we are given that the value of sinA is √3-1/2√2 , and we need to prove that the value of cos2A is √3/2 .

<u>Given</u><u> </u><u>:</u><u>-</u>

• \sf\implies sinA =\dfrac{\sqrt3-1}{2\sqrt2}

<u>To</u><u> </u><u>Prove</u><u> </u><u>:</u><u>-</u><u> </u>

•\sf\implies cos2A =\dfrac{\sqrt3}{2}

<u>Proof </u><u>:</u><u>-</u><u> </u>

We know that ,

\sf\implies cos2A = 1 - 2sin^2A

Therefore , here substituting the value of sinA , we have ,

\sf\implies cos2A = 1 - 2\bigg( \dfrac{\sqrt3-1}{2\sqrt2}\bigg)^2

Simplify the whole square ,

\sf\implies cos2A = 1 -2\times \dfrac{ 3 +1-2\sqrt3}{8}

Add the numbers in numerator ,

\sf\implies cos2A =  1-2\times \dfrac{4-2\sqrt3}{8}

Multiply it by 2 ,

\sf\implies cos2A = 1 - \dfrac{ 4-2\sqrt3}{4}

Take out 2 common from the numerator ,

\sf\implies cos2A = 1-\dfrac{2(2-\sqrt3)}{4}

Simplify ,

\sf\implies cos2A =  1 -\dfrac{ 2-\sqrt3}{2}

Subtract the numbers ,

\sf\implies cos2A = \dfrac{ 2-2+\sqrt3}{2}

Simplify,

\sf\implies \boxed{\pink{\sf cos2A =\dfrac{\sqrt3}{2}} }

Hence Proved !

8 0
3 years ago
How the points are placed in graphing linear inequalities?
Yanka [14]

Answer:

Plot the line y = 2x - 3 and the portion above the line will satisfy the inequality.

5 0
3 years ago
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