Please help i'm having some trouble with this, it's pretty easy!
2 answers:
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Answer:
W = 9533.09 Watt
Explanation:
given,
diameter of pipe inlet, d₁ = 10 cm
r₁ = 5 cm
diameter of pipe outlet, d₂ = 15 cm
r₂= 7.5 cm
head upto water level is to rise = 60 + 5
= 65 m
flow rate = 0.015 m³/s
we know
A₁ v₁ = A₂ v₂ = Q
π r₁² v₁ = π r₂² v₂ = 0.015
v₂ = 0.848 m/s
v₁ = 1.908 m/s
Applying Bernoulli's equation
P_p is the pump pressure
Power of the pump
W = P_p x Q
W = 635539.32 x 0.015
W = 9533.09 Watt
The weight of the meterstick is:
and this weight is applied at the center of mass of the meterstick, so at x=0.50 m, therefore at a distance
from the pivot.
The torque generated by the weight of the meterstick around the pivot is:
To keep the system in equilibrium, the mass of 0.50 kg must generate an equal torque with opposite direction of rotation, so it must be located at a distance d2 somewhere between x=0 and x=0.40 m. The magnitude of the torque should be the same, 0.20 Nm, and so we have:
from which we find the value of d2:
So, the mass should be put at x=-0.04 m from the pivot, therefore at the x=36 cm mark.
and this weight is applied at the center of mass of the meterstick, so at x=0.50 m, therefore at a distance
from the pivot.
The torque generated by the weight of the meterstick around the pivot is:
To keep the system in equilibrium, the mass of 0.50 kg must generate an equal torque with opposite direction of rotation, so it must be located at a distance d2 somewhere between x=0 and x=0.40 m. The magnitude of the torque should be the same, 0.20 Nm, and so we have:
from which we find the value of d2:
So, the mass should be put at x=-0.04 m from the pivot, therefore at the x=36 cm mark.
Answer:
525 V
Explanation:
A = Area =
= Rate of change of magnetic field =
(assumed)
Induced electromotive force is given by
The induced electromotive force is 525 V